如何通過可迭代在Tkinter中創建標簽？

這個想法是通過可迭代在標簽中列印一些輸出變數。它只創建了一個標簽，并不是預期的結果。

我嘗試通過在Cost()函式內部創建標簽來顯示結果，就像print在終端中所做的那樣，假設每次呼叫函式時都會創建標簽。

import numpy as np

from tkinter import *

# configure workspace
root = Tk()
root.title("Print cost")
root.geometry('400x400')
root.configure(bg="#202529")


sizes = ['10x15', '13x18', '15x20', '20x25', '20x30', '30x40']

# depending on the volume of prints the price change, last one is a reference price.
T_10x15_cost = [1000, 700, 600, 600]
T_13x18_cost = [120, 100, 80, 80]
T_15x20_cost = [300, 250, 100, 90]
T_20x25_cost = [1000, 800, 250, 250]
T_20x30_cost = [1200, 1000, 300, 250]
T_30x40_cost = [1500, 1200, 400, 600]

cT = (T_10x15_cost, T_13x18_cost, T_15x20_cost, T_20x25_cost, T_20x30_cost, T_30x40_cost)


# Order per size entry

left_frame = Frame (root, bg="#32383D", bd=2, padx=15, pady=5)
left_frame.place(x=10, y=10)

Label(left_frame, text='10x15').grid(row=1, column=0,padx=5, pady=5)
Label(left_frame, text='13x18').grid(row=2, column=0,padx=5, pady=5)
Label(left_frame, text='15x20').grid(row=3, column=0,padx=5, pady=5)
Label(left_frame, text='20x25').grid(row=4, column=0,padx=5, pady=5)
Label(left_frame, text='20x30').grid(row=5, column=0,padx=5, pady=5)
Label(left_frame, text='30x40').grid(row=6, column=0,padx=5, pady=5)

T_10x15 = IntVar(left_frame, value=0)
T_10x15_box = Entry(left_frame, textvariable=T_10x15, width=5)

T_13x18 = IntVar(left_frame, value=0)
T_13x18_box = Entry(left_frame, textvariable=T_13x18, width=5)

T_15x20 = IntVar(left_frame, value=0)
T_15x20_box = Entry(left_frame, textvariable=T_15x20, width=5)

T_20x25 = IntVar(left_frame, value=0)
T_20x25_box = Entry(left_frame, textvariable=T_20x25, width=5)

T_20x30 = IntVar(left_frame, value=0)
T_20x30_box = Entry(left_frame, textvariable=T_20x30, width=5)

T_30x40 = IntVar(left_frame, value=0)
T_30x40_box = Entry(left_frame, textvariable=T_30x40, width=5)

T_10x15_box.grid(row=1, column=1)
T_13x18_box.grid(row=2, column=1)
T_15x20_box.grid(row=3, column=1)
T_20x25_box.grid(row=4, column=1)
T_20x30_box.grid(row=5, column=1)
T_30x40_box.grid(row=6, column=1)


right_frame = Frame (root, bg="#32383D", bd=2, padx=15, pady=5)
right_frame.place(x=200, y=50)

# cost base on volume for each size

def runCost():

    t_10x15 = int(T_10x15_box.get())
    t_13x18 = int(T_13x18_box.get())
    t_15x20 = int(T_15x20_box.get())
    t_20x25 = int(T_20x25_box.get())
    t_20x30 = int(T_20x30_box.get())
    t_30x40 = int(T_30x40_box.get())

    order = [t_10x15, t_13x18, t_15x20, t_20x25, t_20x30, t_30x40]


    def cost():

        prints = order[i]
        if prints <= 50:
            pricePerVolume = 0
        elif 51 <= prints < 101:
            pricePerVolume = 1
        else:
            pricePerVolume = 2
        cost_ip = prints * price[pricePerVolume]

        #original script without GUI. Leaving this print to check funtionallity
        print(prints, ' --- ', size, 'at store = $', cost_ip, '/// REFprice = $' ,prints * price[3])


        #LABEL CREATION ATTEMP #####

        # 1 option
        # costoIP_label = Label(root, textvariable=cost_ip)

        # 2 option
        costIP_label = Label(left_frame, text=' cost: '   str(cost_ip))

        #placement for any of the option
        costIP_label.grid(row=1, column=3,padx=5, pady=5)


    for i in range(len(order)):
        order[i]
        size = sizes[i]
        price = np.array(cT[i])

        cost()


def clearButton():
    T_10x15_box.delete(0, END)
    T_13x18_box.delete(0, END)
    T_15x20_box.delete(0, END)
    T_20x25_box.delete(0, END)
    T_20x30_box.delete(0, END)
    T_30x40_box.delete(0, END)

def close():
    root.destroy()


bottomFrame = Frame(root, bg="#4C555C", bd=2, padx=5, pady=5)
bottomFrame.place(x=10, y=200)

runCostButton = Button(bottomFrame, text='run', command=runCost)
runCostButton.grid(row=8,column=0, padx=10, pady=10)

clearButton = Button(bottomFrame, text='clear', command=clearButton)
clearButton.grid(row=9,column=0, padx=10, pady=10)

CloseButton = Button(bottomFrame, text="exit", command=close)
CloseButton.grid(row=10,column=0, padx=10, pady=10)


root.mainloop()

uj5u.com熱心網友回復：

1. 不要在 cost() 函式中創建 costIP_label，先在 Entry 欄位之后創建它，并使用 textvariable 僅更改“text”欄位中的值。如果你想讓它在開頭不可見，那么用grid_forget()命令隱藏它或者在里面放一個空字串“”。

2. 您從創建大小串列開始很好，但如果您不打算在程式中更改它，那么元組當然更好。

3. 所有其他物件都依賴于它，如果您基于它創建新物件，那么將來如果它發生變化，您將無需進入程式并更改各種變數，如 T_10x15_cost、T_10x15、T_10x15_box。

   假設 cT 是一個串列串列，可以轉換為字典，其中鍵來自尺寸，值來自價格串列。cT = {尺寸[0] : [1000, 700, 600, 600] ...

4. 最好將元素放在一個回圈中，而不是重復幾乎相同的事情：

for i in range(len(sizes)):
    Label(left_frame, text=sizes[i]).grid(row=i 1, column=0, padx=5, pady=5)

如果我的筆記能以某種方式幫助你，我會很高興。

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