Alamofire5將AFError作為通用錯誤回傳-有解無憂

我正在嘗試開發支持閉包、異步和組合功能的通用網路層。

我希望網路層不依賴任何庫。

協議：

import Combine
import Foundation

protocol NetworkService {
    // Closure
    func get<ResponseModel>(endpoint: String,
                            response: ResponseModel.Type,
                            completion: @escaping (Result<ResponseModel, Error>) -> Void) where ResponseModel: Decodable

    // Async
    func get<ResponseModel>(endpoint: String,
                            response: ResponseModel.Type) async -> Result<ResponseModel, Error> where ResponseModel: Decodable

    // Combine
    func get<ResponseModel>(endpoint: String,
                            response: ResponseModel.Type) -> AnyPublisher<Result<ResponseModel, Error>, Never> where ResponseModel: Decodable
}

在 Alamofire 中實作協議時，出現錯誤。

執行：

import Alamofire
import Combine
import Foundation

final class AlamofireService: NetworkService {
    let session: Session

    // Encoder and Decoder
    let encoder = JSONEncoder()
    let decoder = JSONDecoder()

    init() {
        session = Session()
    }

    // Closure
    func get<ResponseModel>(endpoint: String,
                            response: ResponseModel.Type,
                            completion: @escaping (Result<ResponseModel, Error>) -> Void) where ResponseModel: Decodable
    {
        session
            .request(endpoint, method: .get)
            .validate()
            .responseDecodable(of: response, decoder: decoder) {
                completion($0.result)
            }
    }

    // Async
    func get<ResponseModel>(endpoint: String,
                            response: ResponseModel.Type) async -> Result<ResponseModel, Error> where ResponseModel: Decodable
    {
        let result = await session
            .request(endpoint, method: .get)
            .validate()
            .serializingDecodable(response, decoder: decoder)
            .result

        return result
    }

    // Combine
    func get<ResponseModel>(endpoint: String,
                            response: ResponseModel.Type) -> AnyPublisher<Result<ResponseModel, Error>, Never> where ResponseModel: Decodable
    {
        let result = session
            .request(endpoint, method: .get)
            .validate()
            .publishDecodable(type: response, decoder: decoder)
            .result()

        return result
    }
}

錯誤：

閉包：無法將 'Result<ResponseModel, AFError>' 型別的值轉換為預期的引數型別 'Result<ResponseModel, any Error>'

異步：無法將“Result<ResponseModel, AFError>”型別的回傳運算式轉換為“Result<ResponseModel, any Error>”型別的回傳運算式

組合：無法將 'AnyPublisher<Result<ResponseModel, AFError>, Never>' 型別的回傳運算式轉換為回傳型別 'AnyPublisher<Result<ResponseModel, any Error>, Never>'

我的問題是如何將AFError轉換為Error？

uj5u.com熱心網友回復：

是的，編譯器只是不會自動為您轉換它。最簡單的轉換方法是使用mapError { $0 as Error }.

await session
    .request(endpoint, method: .get)
    .validate()
    .serializingDecodable(response, decoder: decoder)
    .result
    .mapError { $0 as Error }

轉載請註明出處，本文鏈接：https://www.uj5u.com/net/516372.html

標籤：仿制药阿拉莫菲尔斯威夫特5

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