我正在嘗試回傳3個值（州、大小、部門），但僅當州為1個單詞“賓夕法尼亞州”時才有效

我正在嘗試回傳 3 個值（州、大小、部門）。您將在下面的代碼中看到，如果狀態是 1 個單詞“Pennsylvania”，但如果它是 2 個單詞“New York”則不會。您可以注釋掉 New York 并取消注釋 PA 以查看它是否有效。我嘗試使用帶有字串拆分的 if-else。

import json

def lambda_handler(event, context):
    print('## EVENT')
    print(event)
    #salesoutput=event['Details']['ContactData']['Attributes'].get('salesoutput',"Not Available")
    salesoutput= "New York 15 Nuts"
    #salesoutput= "Pennsylvania 15 Nuts"

    if  len(salesoutput.split()) > 3:
        prestate1 = salesoutput.split(' ')[0]
        prestate2 = salesoutput.split(' ')[1]
        State = prestate1   " "   prestate2
        Size = salesoutput.split(' ')[2]
        Department = salesoutput.split(' ')[3]    
#        print("State:",State,"\nDistrict Size:",Size,"\nDepartment:",Department)
    
    else:
        State = salesoutput.split(' ')[0]
        Size = salesoutput.split(' ')[1]
        Department = salesoutput.split(' ')[2]    
#        print("State:",State,"\nDistrict Size:",Size,"\nDepartment:",Department)
    
def describe(Response):
    return State(Response), District(Response), Size(Response)

uj5u.com熱心網友回復：

如果您相當確定輸入格式，為什么不直接使用正則運算式呢？

import re

def lambda_handler(event, context):
    salesoutput= "New York 15 Nuts"
    pattern = re.compile(r'([\w\s] )\s(\d{1,})\s([\w\s] )')
    result = pattern.search(salesoutput)
    State, Size, Department = result.groups()        
    
    print("State:",State,"\nDistrict Size:",Size,"\nDepartment:",Department)    
    
    # TODO implement
    return {
        "State":State,
        "Size":Size,
        "Department": Department
    }

^復制

uj5u.com熱心網友回復：

s1 = "New York 15 Nuts"
s2 = "Pennsylvania 15 Nuts"
for s in [s1, s2]:
    *State, Size, Department = s.split(" ")
    print("State:"," ".join(State),"\nDistrict Size:",Size,"\nDepartment:",Department)

uj5u.com熱心網友回復：

看起來你可以rsplit使用maxsplit：

>>> s = "New York 15 Nuts"
>>> s.rsplit(maxsplit=2)
['New York', '15', 'Nuts']

>>> s = "Pennsylvania 15 Nuts"
>>> s.rsplit(maxsplit=2)
['Pennsylvania', '15', 'Nuts']

uj5u.com熱心網友回復：

如果部門總是一個詞，可以根據拆分陣列的長度來決定做什么。

此解決方案是一種快速修復。

更理想的解決方案是用逗號分隔資料（如果您有權訪問該資料），并使用 salesoutput.split(',')。

注意：我只會將陣列拆分一次，這樣您就不會創建同一個拆分陣列的多個副本，以節省時間和空間。

import json

def lambda_handler(event, context):
    print('## EVENT')
    print(event)
    #salesoutput=event['Details']['ContactData']['Attributes'].get('salesoutput',"Not Available")
    salesoutput= "New York 15 Nuts"
    #salesoutput= "Pennsylvania 15 Nuts"
    
    sales = salesoutput.split(' ')
    if len(sales) == 3:
        State = sales[0]
        Size = sales[1]
        Department = sales[2]
    elif len(sales) == 4:
        State = sales[0]   " "   sales[1]
        Size = sales[2]
        Department = sales[3]
        
    print("State:",State,"\nDistrict Size:",Size,"\nDepartment:",Department)    
    
    # TODO implement
    return {
        "State":State,
        "Size":Size,
        "Department": Department
        #"Email":response["Item"]["Email"]
        #'statusCode': 200,
        #'body': json.dumps('Hello from Lambda!')
    }

uj5u.com熱心網友回復：

@Repl.it

謝謝你這樣做了，它只需要針對 json 輸入進行調整。這只是表明我對Python的缺乏經驗......

import json
import re

def lambda_handler(event, context):
    salesoutput=event['Details']['ContactData']['Attributes'].get('salesoutput',"Not Available")
    pattern = re.compile(r'([\w\s] )\s(\d{1,})\s([\w\s] )')
    result = pattern.search(salesoutput)
    State, Size, Department = result.groups()        
    
    print("State:",State,"\nDistrict Size:",Size,"\nDepartment:",Department)    
    
    # TODO implement
    return {
        "State":State,
        "Size":Size,
        "Department": Department
    }

標籤：Pythonif 语句strsplit

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