例如，我有一個字串“asdf123d6lkj006m90”，我需要以下結果 [123, 6, 0, 0, 6, 90]。我試過了：
let str = "asdf123d6lkj006m90"
let func = function(inputString){
let outputArray = []
let currentNumber = ""
for(let element of inputString){
if(Number(element)||element == 0){
outputArray.push(Number(element))
}
}
return(outputArray)
}
console.log(func(str))
但它回傳 [ 1, 2, 3, 6, 0, 0, 6, 9, 0 ] 我如何收到正確的數字？
uj5u.com熱心網友回復：
您一次查看每個字符，同時您還應該檢查接下來的幾個字符。
const str = "asdf123d6lkj006m90";
console.log(numbers(str));
function numbers(str) {
const nums = []; // create an array with the numbers
for(let i = 0; i < str.length; i ) {
// in your example you want preceding 0s to be their own number
if(str[i] == 0) {
nums.push(0);
continue;
}
let current = ""; // add to our string
while(!isNaN(str[i])) {
// as long as the character can be converted to a number
current = str[i ];
}
// if there were any numbers added
if(current.length)
nums.push( current);
}
return nums;
}請注意，雖然由于嵌套回圈，這看起來像 O(n^2)，但它實際上仍然是線性的，因為回圈遍歷同一個陣列，一個回圈從另一個停止的地方開始。
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