如何將檔案從bash轉換為json

我有一個這樣的.file并想將其轉換為 JSON 格式。

2022/01/22 21:27:56 [notice] 40#40: signal process started
2022/01/22 21:27:56 [error] 40#40: open() "/run/nginx.pid" failed (2: No such file or directory)
2022/01/22 21:28:04 [notice] 42#42: signal process started
2022/01/22 21:28:04 [error] 42#42: open() "/run/nginx.pid" failed (2: No such file or directory)

代碼

#!/bin/bash
json=''
while read -r line; do
    dt=$(echo ${line} | awk '{print ($1" "$2)}')
    info=$(echo ${line} | awk '{print ($3)}')
    error=$(echo ${line} | awk '{print ($4$5$6$7$8$9$10)}')
    json ="{\"date\":\"$dt\","\"info\":\"$info\",\"error\":\"$error\""}"
done < "$file"
    
res="$json"

如何使 var res像帶有分隔符逗號 "," 每個物件 {} 的 JSON 格式

我想做這樣的輸出

[{"date":"2022/01/22 21:27:56","info":"[notice]","error":"40#40:signalprocessstarted"},
{"date":"2022/01/22 21:27:56","info":"[error]","error":"40#40:open()"/run/nginx.pid"failed(2:Nosuch"},
{"date":"2022/01/22 21:28:04","info":"[notice]","error":"42#42:signalprocessstarted"},
{"date":"2022/01/22 21:28:04","info":"[error]","error":"42#42:open()"/run/nginx.pid"failed(2:Nosuch"}]

但現在我的輸出看起來像這樣

{"date":"2022/01/22 21:27:56","info":"[notice]","error":"40#40:signalprocessstarted"}{"date":"2022/01/22 21:27:56","info":"[error]","error":"40#40:open()"/run/nginx.pid"failed(2:Nosuch"}{"date":"2022/01/22 21:28:04","info":"[notice]","error":"42#42:signalprocessstarted"}{"date":"2022/01/22 21:28:04","info":"[error]","error":"42#42:open()"/run/nginx.pid"failed(2:Nosuch"}

物件之間沒有任何分隔符

以及如何在 JSON中處理像“/run/nginx.pid”這樣的字串

uj5u.com熱心網友回復：

請您嘗試以下方法：

#!/bin/bash

echo -n "["
while read -r day hms info err; do              # split on blank characters up to 4 words
    if (( nr   )); then                         # count the line number
        echo ","                                # append a comma after the previous line
    fi
    err="$(sed -E 's/"/\\&/g' <<< "$err")"      # escape double quotes in the message
    printf '{"date":"%s %s","info":"%s","error":"%s"}' "$day" "$hms" "$info" "$err"
done < file
echo "]"

輸出：

[{"date":"2022/01/22 21:27:56","info":"[notice]","error":"40#40: signal process started"},
{"date":"2022/01/22 21:27:56","info":"[error]","error":"40#40: open() \"/run/nginx.pid\" failed (2: No such file or directory)"},
{"date":"2022/01/22 21:28:04","info":"[notice]","error":"42#42: signal process started"},
{"date":"2022/01/22 21:28:04","info":"[error]","error":"42#42: open() \"/run/nginx.pid\" failed (2: No such file or directory)"}]

[編輯]
如果你想為var生成的 json 格式的字串分配一個變數（例如，），請將整個代碼用$(and括起來)，command substitution然后將變數分配給它，例如：

var=$(
echo -n "["
while read -r day hms info err; do              # split on blank characters up to 4 words
    if (( nr   )); then                         # count the line number
        echo ","                                # append a comma after the previous line
    fi
    err="$(sed -E 's/"/\\&/g' <<< "$err")"      # escape double quotes in the message
    printf '{"date":"%s %s","info":"%s","error":"%s"}' "$day" "$hms" "$info" "$err"
done < file
echo "]"
)
echo "$var"                                     # just to see the result

如果jq可用，您還可以說：

echo -n "["
while read -r day hms info err; do              # split on blank characters up to 4 words
    if (( nr   )); then                         # count the line number
        echo ","                                # append a comma after the previous line
    fi
    jq -cn --arg date "$day $hms" --arg info "$info" --arg error "$err" '{date:$date, info:$info, error:$error}'
done < file
echo "]"

正如戈登戴維森所建議的那樣。

標籤：

上一篇：根據鏈接表中的PK，使用FK在Access中顯示鏈接表中的記錄

下一篇：除了“，”之外，如何在最后一個值之前列印“和”？[復制]