除了“，”之外，如何在最后一個值之前列印“和”？[復制]

public static void main(String[] args) {       
        Scanner sc = new Scanner(System.in);
        System.out.println("How old are you?");
        int age = sc.nextInt();
        System.out.println("What is your favorite number?");
        int favnum = sc.nextInt();
        int max, min;
        String sequence ="";
        if (favnum > age) {
            max = favnum;
            min = age;
        } else {
            max = age;
            min = favnum;
        }
        System.out.print("The values between "   max   " and "   min   " that are divisible by 4 are ");
        for (int i = max; i >= min; i--) {
            if (i % 4 == 0) {
                System.out.print(i  ", ");
            }
            
            if(i % 4 == 0 && i / 4 == 1) {
                System.out.print("and "  i  ".");
            }
        }    
   }
}

例如，如果輸入值介于 21 和 6 之間。我希望它列印“可被 4 整除的 21 和 6 之間的值是 20、16、12和 8。最后一位數字有一個和和一個句點結束。

這是我代碼的一小部分，但我一直堅持這部分我嘗試了很多方法來做到這一點，但它對我不起作用。

這是它列印的內容：

How old are you?
21
What is your favorite number?
6
The values between 21 and 6 that are divisible by 4 are 20, 16, 12, 8,

我想要它列印的內容：

The values between 21 and 6 that are divisible by 4 are 20, 16, 12, and 8.

uj5u.com熱心網友回復：

您需要以不同的方式執行此操作，并將所有可整除的數字添加到串列中，然后漂亮地列印串列，如下例所示：

public static void main(String[] args) {
    int max = 20;
    int min = 1;
    List<Integer> divisibleBy4 = new ArrayList<>();
    for (int i = max; i >= min; i--) {
        if (i % 4 == 0) {
            divisibleBy4.add(i);
        }
    }

    for (int j = 0; j < divisibleBy4.size(); j  ) {
        if (j == 0) {
            System.out.print(divisibleBy4.get(j));
        } else if (j == divisibleBy4.size() - 1) {
            System.out.print(" and "  divisibleBy4.get(j)  ".");
        } else {
            System.out.print(", "   divisibleBy4.get(j));
        }
    }
}

將此添加到您的代碼中將產生以下作業代碼：

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("How old are you?");
        int age = sc.nextInt();
        System.out.println("What is your favorite number?");
        int favnum = sc.nextInt();
        int max, min;
        String sequence ="";
        if (favnum > age) {
            max = favnum;
            min = age;
        } else {
            max = age;
            min = favnum;
        }
        System.out.print("The values between "   max   " and "   min   " that are divisible by 4 are ");
        List<Integer> divisibleBy4 = new ArrayList<>();
        for (int i = max; i >= min; i--) {
            if (i % 4 == 0) {
                divisibleBy4.add(i);
            }
        }

        for (int j = 0; j < divisibleBy4.size(); j  ) {
            if (j == 0) {
                System.out.print(divisibleBy4.get(j));
            } else if (j == divisibleBy4.size() - 1) {
                System.out.print(" and "  divisibleBy4.get(j)  ".");
            } else {
                System.out.print(", "   divisibleBy4.get(j));
            }
        }
    }
}

uj5u.com熱心網友回復：

您正在做的事情的困難在于，在開始回圈之前，您不知道序列中有多少個四的倍數。這使您難以處理這些情況：

• 不存在四的倍數

• 只有四的倍數（因此不需要“和”）

• 以不同方式處理最后一個倍數（如您所知）

為了解決這個問題，我會像這樣重構你的代碼（請原諒任何錯別字——我是用手機寫的）。

// figure out how many multiples of four exist within the range
int firstMultiple = max - (max % 4);

// handle no fours being present
if (firstMultiple < min) { ... }

int countFours = (firstMultiple - min) / 4;
countFours  ; // add one since we started from a multiple

// loop for printing all but the last one
int stopAt = countFours - 1;
for (int i = 0; i < stopAt; i  ) {
    // print with commas inside this loop
    int thisMultiple = firstMultiple - (4 * i);
}

if (countFours > 1) { /* print and here */ }

// print the final four
int finalFour = firstMultiple - (4 * stopAt); 

uj5u.com熱心網友回復：

對于最后一個數字，您必須檢查 i 和 min 之間的差異是否小于 4 。因此，您可以在 for 回圈陳述句中添加以下內容。

public class Swtich {
    public static void main(String[] args) {

        System.out.println("How old are you?");
        Scanner sc = new Scanner(System.in);
        int age = sc.nextInt();
        System.out.println("What is your favorite number?");
        int favnum = sc.nextInt();
        int max, min;
        String sequence = "";
        if (favnum > age) {
            max = favnum;
            min = age;
        } else {
            max = age;
            min = favnum;
        }
        System.out.print("The values between "   max   " and "   min   " that are divisible by 4 are ");
        StringBuilder sb = new StringBuilder();
        for (int i = max; i >= min; i--) {
            if (i % 4 == 0 && (i - min) <= 4) {

                sb.delete(sb.length() - 2, sb.length());
                sb.append(" and "   i   ".");
            } else if (i % 4 == 0) {
                sb.append(i   ", ");

            }

        }
        System.out.println(sb.toString());
    }
}

輸出如下：

How old are you?
21
What is your favorite number?
6
The values between 21 and 6 that are divisible by 4 are 20, 16, 12 and 8.

uj5u.com熱心網友回復：

    int counter=0; //add this counter 

    System.out.println("How old are you?");
    int age = sc.nextInt();
    System.out.println("What is your favorite number?");
    int favnum = sc.nextInt();
    int max, min;
    String sequence ="";
    if (favnum > age) {
        max = favnum;
        min = age;
    } else {
        max = age;
        min = favnum;
    }
    System.out.print("The values between "   max   " and "   min   " that are divisible by 4 are ");
    for (int i = max; i >= min; i--) {
        if(i % 4==0) {
            counter  ; //Number of values that are divisible by 4.
        }
    }
    for (int i = max; i >= min; i--) {
        if(i % 4 == 0 && counter==1) {
            System.out.print("and "  i  ".");
        }else
        {
            if (i % 4 == 0) {
                System.out.print(i  ", ");
                counter--;
            }
        }
        
     }

這是輸出：

How old are you?
30
What is your favorite number?
4
The values between 30 and 4 that are divisible by 4 are 28, 24, 20, 16, 
12, 8, and 4.

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