C語言自動發牌程式，供大家參考，具體內容如下：
一副撲克有52張牌，打橋牌時應將牌分給4個人，請設計一個程式完成自動發牌的作業，要求：黑桃用S (Spaces)表示，紅桃用H (Hearts)表示，方塊用D (Diamonds)表示，梅花用C (Clubs)表示，
分析：
要設定陣串列現撲克牌
要設定陣串列現玩家
要給撲克牌做特定標識，得到結果后玩家要知道自己手中黑桃有哪些、方塊有哪些
初步想法：
設定4個字符陣列保存4種梅花牌，設定4個字符陣串列示4名玩家分配到的牌
每張牌隨機發給4名玩家，當玩家的持牌數達到13，不再分配給該名玩家牌
代碼展示：
void mycode_13() { srand(unsigned(time(NULL))); /*全部牌*/ char S[13] = { '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A' }; char H[13] = { '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A' }; char D[13] = { '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A' }; char C[13] = { '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A' }; /*4個玩家*/ char player1[13], player2[13], player3[13], player4[13]; int p1 = 0, p2 = 0, p3 = 0, p4 = 0; distribution(S, player1, player2, player3, player4, &p1, &p2, &p3, &p4); distribution(H, player1, player2, player3, player4, &p1, &p2, &p3, &p4); distribution(D, player1, player2, player3, player4, &p1, &p2, &p3, &p4); distribution(C, player1, player2, player3, player4, &p1, &p2, &p3, &p4); puts("運行結束"); for (int i = 0; i < 13; i++) printf("%c ", player1[i]); putchar('\n'); for (int i = 0; i < 13; i++) printf("%c ", player2[i]); putchar('\n'); for (int i = 0; i < 13; i++) printf("%c ", player3[i]); putchar('\n'); for (int i = 0; i < 13; i++) printf("%c ", player4[i]); } void distribution(char * S_H_D_C, char * player1, char * player2, char * player3, char * player4, int *p1, int *p2, int *p3, int *p4) { static int h = 1; int r; int a = *p1, b = *p2, c = *p3, d = *p4; for (int i = 0; i < 13; i++) { r = (rand() % 4) + 1; while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13)) r = (rand() % 4) + 1; switch (r) { case 1: player1[(*p1)++] = S_H_D_C[i]; break; case 2: player2[(*p2)++] = S_H_D_C[i]; break; case 3: player3[(*p3)++] = S_H_D_C[i]; break; case 4: player4[(*p4)++] = S_H_D_C[i]; break; default: break; } } switch (h++) { case 1: printf("黑桃：\n"); break; case 2: printf("紅桃：\n"); break; case 3: printf("方塊：\n"); break; case 4: printf("梅花：\n"); break; } printf("Player1:"); for (int i = a; i < (*p1); i++) printf("%c ", player1[i]); putchar('\n'); printf("Player2:"); for (int i = b; i < (*p2); i++) printf("%c ", player2[i]); putchar('\n'); printf("Player3:"); for (int i = c; i < (*p3); i++) printf("%c ", player3[i]); putchar('\n'); printf("Player4:"); for (int i = d; i < (*p4); i++) printf("%c ", player4[i]); putchar('\n'); }
以下代碼保證了當某個人得到13張牌后不在得牌：
r = (rand() % 4) + 1; while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13)) r = (rand() % 4) + 1;
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