一.如何實作
1.說明:由于本文只是對初學C語言的人學習,所以將不會涉及任何演算法,電腦將采用隨機下子的方式,(后期會為大家介紹Alpha-Beta剪枝演算法實作人工智能AI)
2.主要部分:
(1)選單
(2)列印棋盤
(3)玩家下子
(4)電腦下子
(5)判斷輸贏
二.實作代碼及分析
(1)選單的制作


運用do…while回圈呼叫選單,根據用戶選擇實作玩游戲和退出游戲
(2)棋盤的初始化和列印
棋盤采用標準的15*15的格子,我們可以宏定義ROW和COL分別為15和15來表示行和列,

分別封裝兩個函式對棋盤進行初始化和列印
初始化:(這里將棋盤初始化為空格,可初始化為其他)

列印棋盤:

效果如下:

(3)玩家下子
void PlayerMove(char board[ROW][COL], int row, int col) {
int x, y;
while (1) {
printf("玩家走:\n");
printf("請輸入坐標:\n");
scanf("%d %d", &x, &y);
if (x >= 1 && x <= row && y >= 1 && y <= col) {
if (board[x - 1][y - 1] == ' ') {
board[x - 1][y - 1] = 'O';
break;
}
else {
printf("坐標被占用,請重新輸入\n");
}
}
else {
printf("坐標非法,請重新輸入\n");
}
}
}
玩家下子主要采用的思路是,判斷棋盤上是否有子,已經輸入的坐標是否合法,
(4)電腦下子
void ComputerMove(char board[ROW][COL], int row, int col) {
int x, y;
printf("電腦走\n");
while (1) {
x = rand() % row;
y = rand() % col;
if (board[x][y] == ' ') {
board[x][y] = 'X';
break;
}
}
}
與玩家下子相同,此處采用的隨機下子,后期可進行優化(比如:極大極小值演算法、Alpha-Beta剪枝演算法等)
(5)判斷輸贏
通過遍歷整個棋盤,觀察是否有連五子情況出現,代碼如下:
char iswin(char board[ROW][COL], int row, int col) {
//行
int ren=0,dian=0,i,j;
for (i = 0;i < row;i++) {
ren = 0;
for (j = 0;j < col;j++) {
if (board[i][j] == 'O')
ren++;
else
ren = 0;
if (ren >= 5)
return 'o';
}
}
for (i = 0;i < row;i++) {
dian = 0;
for (j = 0;j < col;j++) {
if (board[i][j] == 'X')
dian++;
else
dian = 0;
if (dian >= 5)
return 'x';
}
}
//列
ren = dian = 0;
for (i = 0;i < row;i++) {
ren = 0;
for (j = 0;j < col;j++) {
if (board[j][i] == 'O')
ren++;
else
ren = 0;
if (ren >= 5)
return 'o';
}
}
for (i = 0;i < row;i++) {
dian = 0;
for (j = 0;j < col;j++) {
if (board[j][i] == 'X')
dian++;
else
dian = 0;
if (dian >= 5)
return 'x';
}
}
//右下
ren = dian =i=j= 0;
for (int k = 0;k < row;k++) {
i = k;
j = 0;
ren = 0;
while (i < row && j < col) {
if (board[i][j] == 'O') {
ren++;
}
else {
ren = 0;
}
i++;
j++;
if (ren >= 5)
return 'o';
}
}
i = j = 0;
for (int k = 0;k < row;k++) {
i = k;
j = 0;
dian = 0;
while (i < row && j < col) {
if (board[i][j] == 'X') {
dian++;
}
else
dian = 0;
i++;
j++;
if (dian >= 5)
return 'x';
}
}
//右上
for (int k = row;k >=0;k--) {
j = col;
i = k;
ren = 0;
while (i >=0 && j >=0) {
if (board[i][j] == 'O') {
ren++;
}
else
ren = 0;
i--;
j--;
if (ren >= 5)
return 'o';
}
}
for (int k = row;k >= 0;k--) {
i = k;
j = col;
dian = 0;
while (i >= 0 && j >= 0) {
if (board[i][j] == 'X') {
dian++;
}
else
dian = 0;
i--;
j--;
if (dian >= 5)
return 'o';
}
}
return 'c';
//左
}
三.整個代碼
(1)test.c檔案下代碼:
#define _CRT_SECURE_NO_WARNINGS 1
#include"game.h"
void menu() {
printf("**************************\n");
printf("******* 1. play *********\n");
printf("******* 0. exit *********\n");
printf("**************************\n");
}
void game() {
//棋盤陣列
char board[ROW][COL],ret;
//初始化棋盤
InitBoard(board, ROW, COL);
//列印棋盤
PrintBoard(board, ROW, COL);
//下棋
int a;
printf("1.先手 0.后手");
scanf("%d", &a);
if(a==1)
PlayerMove(board, ROW, COL);
else
ComputerMove(board, ROW, COL);
while (1) {
if (a == 0) {
//PlayerMove(board, ROW, COL);
PlayerMove(board, ROW, COL);
PrintBoard(board, ROW, COL);
ret=iswin(board, ROW, COL);
if (ret != 'c') {
break;
}
//ComputerMove(board, ROW, COL);
ComputerMove(board, ROW, COL);
PrintBoard(board, ROW, COL);
ret = iswin(board, ROW, COL);
if (ret != 'c') {
break;
}
}
else {
//ComputerMove(board, ROW, COL);
ComputerMove(board, ROW, COL);
PrintBoard(board, ROW, COL);
ret = iswin(board, ROW, COL);
if (ret != 'c') {
break;
}
//PlayerMove(board, ROW, COL);
PlayerMove(board, ROW, COL);
PrintBoard(board, ROW, COL);
ret = iswin(board, ROW, COL);
if (ret != 'c') {
break;
}
}
}
if (ret == 'o')
printf("玩家贏\n");
else if (ret == 'x')
printf("電腦贏\n");
else
printf("平局\n");
}
int main() {
int input;
srand((unsigned int)time(NULL));
do {
menu();
scanf("%d", &input);
switch (input) {
case 1:
game();
break;
case 0:
printf("退出游戲\n");
break;
default:
printf("選擇錯誤\n");
break;
}
} while (input);
return 0;
}
(2)game.c下的代碼
#define _CRT_SECURE_NO_WARNINGS 1
#include"game.h"
void InitBoard(char board[ROW][COL], int row, int col) {
for (int i = 0;i < row;i++) {
for (int j = 0;j < col;j++) {
board[i][j] = ' ';
}
}
}
void PrintBoard(char board[ROW][COL], int row, int col) {
for (int i = 0;i < row;i++) {
printf(" ");
printf("%2d", i+1);
}
printf("\n");
for (int i = 0;i < row;i++) {
//列印資料
printf("%2d", i + 1);
for (int j = 0;j < col;j++) {
printf(" %c ", board[i][j]);
if (j < col - 1)
printf("|");
}
printf("\n");
//列印分割行
if (i < row - 1) {
printf(" ");
for (int j = 0;j < col;j++) {
printf("---");
if (j < col-1)
printf("|");
}
printf("\n");
}
}
}
void PlayerMove(char board[ROW][COL], int row, int col) {
int x, y;
while (1) {
printf("玩家走:\n");
printf("請輸入坐標:\n");
scanf("%d %d", &x, &y);
if (x >= 1 && x <= row && y >= 1 && y <= col) {
if (board[x - 1][y - 1] == ' ') {
board[x - 1][y - 1] = 'O';
break;
}
else {
printf("坐標被占用,請重新輸入\n");
}
}
else {
printf("坐標非法,請重新輸入\n");
}
}
}
void ComputerMove(char board[ROW][COL], int row, int col) {
int x, y;
printf("電腦走\n");
while (1) {
x = rand() % row;
y = rand() % col;
if (board[x][y] == ' ') {
board[x][y] = 'X';
break;
}
}
}
char iswin(char board[ROW][COL], int row, int col) {
//行
int ren=0,dian=0,i,j;
for (i = 0;i < row;i++) {
ren = 0;
for (j = 0;j < col;j++) {
if (board[i][j] == 'O')
ren++;
else
ren = 0;
if (ren >= 5)
return 'o';
}
}
for (i = 0;i < row;i++) {
dian = 0;
for (j = 0;j < col;j++) {
if (board[i][j] == 'X')
dian++;
else
dian = 0;
if (dian >= 5)
return 'x';
}
}
//列
ren = dian = 0;
for (i = 0;i < row;i++) {
ren = 0;
for (j = 0;j < col;j++) {
if (board[j][i] == 'O')
ren++;
else
ren = 0;
if (ren >= 5)
return 'o';
}
}
for (i = 0;i < row;i++) {
dian = 0;
for (j = 0;j < col;j++) {
if (board[j][i] == 'X')
dian++;
else
dian = 0;
if (dian >= 5)
return 'x';
}
}
//右下
ren = dian =i=j= 0;
for (int k = 0;k < row;k++) {
i = k;
j = 0;
ren = 0;
while (i < row && j < col) {
if (board[i][j] == 'O') {
ren++;
}
else {
ren = 0;
}
i++;
j++;
if (ren >= 5)
return 'o';
}
}
i = j = 0;
for (int k = 0;k < row;k++) {
i = k;
j = 0;
dian = 0;
while (i < row && j < col) {
if (board[i][j] == 'X') {
dian++;
}
else
dian = 0;
i++;
j++;
if (dian >= 5)
return 'x';
}
}
//右上
for (int k = row;k >=0;k--) {
j = col;
i = k;
ren = 0;
while (i >=0 && j >=0) {
if (board[i][j] == 'O') {
ren++;
}
else
ren = 0;
i--;
j--;
if (ren >= 5)
return 'o';
}
}
for (int k = row;k >= 0;k--) {
i = k;
j = col;
dian = 0;
while (i >= 0 && j >= 0) {
if (board[i][j] == 'X') {
dian++;
}
else
dian = 0;
i--;
j--;
if (dian >= 5)
return 'o';
}
}
return 'c';
//左
}
(3)game.h下的代碼
#pragma once
#define ROW 15
#define COL 15
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
//初始化棋盤
void InitBoard(char board[ROW][COL], int row, int col);
//列印棋盤
void PrintBoard(char board[ROW][COL], int row, int col);
//人走
void PlayerMove(char board[ROW][COL], int row, int col);
//電腦走
void ComputerMove(char board[ROW][COL], int row, int col);
//判斷輸贏
char iswin(char board[ROW][COL], int row, int col);
四.具體效果
1.棋盤列印以及選擇先后手

2.玩家和電腦下子

3.判斷輸贏

此處我們看到玩家贏了,可是電腦實在太蠢了,所以還有很多地方需要添加的
歡迎各位大佬對此代碼進行優化!
轉載請註明出處,本文鏈接:https://www.uj5u.com/qita/290964.html
標籤:其他
上一篇:IOT 示例
