在猜數列游戲1的基礎上，設定一個陣列用來存放6個數列的第2到第4個數，在用戶要求猜測新數列的情況下，回圈顯示各數列的前兩個數，要求用戶猜測第3個數， 6個數列3個組成的陣列為：{1,2,3,3,4,7,2,5,12,3,6,10,4,9,16,5,12,22}
輸入格式:
根據要求輸入整數數值為字符Y或N
輸出格式:
各提示資訊與猜數列游戲1一致，
輸入樣例:
在這里給出一組輸入，例如：
3
Y
7
Y
12
Y
10
Y
16
Y
22
Y
5
Y
3
N輸出樣例:
在這里給出相應的輸出，例如：
The first 2 value is 1,2.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 3,4.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 2,5.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 3,6.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 4,9.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 5,12.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,2.What is the next value?
Nice guess but not quite it.
Do you want to guess again?
Want to try another sequence?(Y/N)
num_of_rights:7 num_of_tries:8代碼實作（C++）
#include <iostream>
#include <cstdio>
using namespace std;
int main()
{
int a1=3,a2=5,i=0,num,sum_t=0,sum_Y=0;
int a[18]={1,2,3,3,4,7,2,5,12,3,6,10,4,9,16,5,12,22};
int count=0;
char ch,ch2;
bool go1=true,go2=true;
while(1)
{
if(i<1)
cout << "The first 2 value is " << a[count] << ',' << a[count+1] << ".What is the next value?" << endl;
i++;
if(i<=100&&i>=1)
cin >> num;
while(1)
{
if(num!=a[count+2]&&i==1)
{
printf("Nice guess but not quite it.\n");
sum_t++;
}
if(num!=a[count+2]&&i==2)
{
printf("Wrong a second time.\n");
sum_t++;
}
if(num!=a[count+2]&&i==3)
{
printf("This is harder than it looks.\n");
sum_t++;
}
if(num!=a[count+2]&&i==4)
{
sum_t++;
printf("It must be getting pretty frustrating by now!\n");
}
if(num!=a[count+2])
{
printf("Do you want to guess again?\n");
cin >> ch2;
if(ch2=='Y')
{
break;
}
}
if(num == a[count+2]||ch2=='N')
{
i=0;
if(num==a[count+2])
{
sum_Y++;
sum_t++;
}
printf("Want to try another sequence?(Y/N)\n");
if(count<15)
{
count+=3;
}
else count=0;
cin >> ch;
if(ch == 'Y')
break;
else
{
printf("num_of_rights:%d num_of_tries:%d",sum_Y,sum_t);
exit(0);
}
}
}
}
return 0;
}轉載請註明出處，本文鏈接：https://www.uj5u.com/qita/302032.html
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