平臺上至少還有 2 個問題，但他們的回答都沒有幫助我。
我剛匯入：
from selenium.common.exceptions import NoSuchElementException
然后使用：
if Newest_tab_button:
print('element found')
else:
print('not found')
或者
try:
wait = WebDriverWait(driver, 15)
Newest_tab_button = wait.until(EC.visibility_of_element_located((By.XPATH, '//*[@text="NEWEST"]//ancestor::*[contains(@resource-id, "itemContainer")]')))
except NoSuchElementException:
print('Element not found')
沒有任何效果，仍然得到：
selenium.common.exceptions.TimeoutException: Message:
任何人都可以幫助我嗎？提前致謝。
uj5u.com熱心網友回復：
您可以在同except一塊或多個except塊中捕獲多個例外
try:
wait = WebDriverWait(driver, 15)
Newest_tab_button = wait.until(EC.visibility_of_element_located((By.XPATH, '//*[@text="NEWEST"]//ancestor::*[contains(@resource-id, "itemContainer")]')))
except TimeoutException as e:
print("TimeoutException")
except NoSuchElementException as e1:
print("NoSuchElementException")
except Exception as e3: # To catch an Exception other than the specified once.
print(e3)
或者您需要將所有例外放在一個元組中：
except (TimeoutException,NoSuchElementException): # This catches either TimeoutException or NoSuchElementException
print("ERROR")
uj5u.com熱心網友回復：
在第二種方法中，您只是在捕獲，NoSuchElementException但問題是您的腳本超時并且您收到了TimeoutException，您只需要捕獲它以繼續腳本
from selenium.common.exceptions import NoSuchElementException, TimeoutException
try:
wait = WebDriverWait(driver, 15)
Newest_tab_button = wait.until(EC.visibility_of_element_located((By.XPATH, '//*[@text="NEWEST"]//ancestor::*[contains(@resource-id, "itemContainer")]')))
except (NoSuchElementException, TimeoutException) as error:
print(error)
# Continue with the script
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