我想使用type_name屬性獲得回應,而不在表中添加新欄位
{
"status": 200,
"message": "OK",
"data": {
"id": 23,
"uuid": "9b1d33f9-0e44-4161-9936-ec41309697a5",
"sender_id": null,
"receiver_id": 2,
"type": 0,
"coin": 200,
"balance": 27000,
"description": "Topup 200 coin",
"type_name": "Topup"
}
因此我嘗試在 CoinTransaction 模型中創建一個名為 typeName() 的方法,希望可以通過 with() 方法呼叫該方法,如下所示:
$transaction = CoinTransaction::create([
'receiver_id' => auth()->user()->id,
'coin' => $request->coin,
'balance' => $predefineCoin->balance ?? 1000,
'type' => 0,
'description' => $request->description
]);
$transaction = CoinTransaction::with(['typeName'])->find($transaction->id);
但它回傳一個錯誤:
Error: Call to a member function addEagerConstraints() on string...
在我的 CoinTransaction 模型中
class CoinTransaction extends Model
{
use HasFactory;
protected $guarded = ['id'];
public function sender() {
return $this->belongsTo(User::class, 'sender_id');
}
public function receiver() {
return $this->belongsTo(User::class, 'receiver_id');
}
public function typeName() {
$typeName = null;
switch($this->type){
case 0: $typeName = 'Topup'; break;
default: $typeName = 'Unknown';
}
return $typeName;
}
}
uj5u.com熱心網友回復:
typeName不是relationship method你typeName()喜歡下面的
$coin=CoinTransaction::find($transaction->id);
dd($coin->typeName());
或者
要將type_name屬性添加到現有回應,您可以使用 Mutators
參考:https : //laravel.com/docs/8.x/eloquent-mutators#accessors-and-mutators
所以添加下面的屬性和方法 CoinTransaction
protected $appends = ['type_name'];
和方法
public function getTypeNameAttribute()
{
$typeName = null;
switch($this->type){
case 0: $typeName = 'Topup'; break;
default: $typeName = 'Unknown';
}
return $typeName;
}
所以在控制器中
$transaction = CoinTransaction::find($transaction->id);
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