得到一個錯誤說
calculator.c:11:9: 警告：'num1' 的型別默認為 'int' [-Wimplicit-int] 11 | 整數加法(num1, num2)"
代碼仍然會運行，但想知道為什么會出現這種情況？
#include <stdio.h>
int main()
{
int num1;
int num2;
int addition(num1, num2)
{
return num1 num2;
}
int subtraction(num1, num2)
{
return num1-num2;
}
int multiply(num1, num2)
{
return num1*num2;
}
float devide(num1, num2)
{
return num1/num2;
}
printf("Still works");
}
uj5u.com熱心網友回復：
首先，不要把你的函式放在 main. 每個函式都應該是獨立的：
#include <stdio.h>
int addition(num1, num2) // Function BEFORE main, not inside main
{
return num1 num2;
}
int main()
{
int num1;
int num2;
....
}
其次，在宣告函式時，為每個引數指定一個型別：
int addition(int num1, int num2) // Declared each parameter as "int"
{
return num1 num2;
}
最后，為了代碼的長期可用性，名稱要一致和正確。
// You named the first two functions addition and subtraction
// so this one should be "multiplication", not "multiply"!
// A sudden change in naming convention means poor design!
int multiply(num1, num2)
// The proper spelling of the operation is "divide" or "division"
// You will make other programmers jobs extremely difficult
// if they cannot tell what function this is, because of a misspelling.
float devide(num1, num2)
將所有這些變化放在一起：
#include <stdio.h>
int addition(int num1, int num2)
{
return num1 num2;
}
int subtraction(int num1, int num2)
{
return num1-num2;
}
int multiplication(int num1, int num2)
{
return num1*num2;
}
float division(int num1, int num2)
{
return (float)num1/num2;
}
int main()
{
int num1;
int num2;
printf("Still works");
return 0;
}
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標籤：C