我有一個包含物件陣列的物件。我試圖在不手動迭代陣列和物件的情況下找到物件屬性的最高值“sortOrder”。
所以我的變數如下所示:
const myObj = {
people: [
0: {firstname: 'Dave', lastName: 'Jones', sortOrder: 22},
1: {firstname: 'Jane', lastName: 'Smith', sortOrder: 11}
],
otherPeople: [
0: {firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33},
1: {firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12}
]
};
所以我會嘗試遍歷這個,最終找到,在這種情況下,最高的 sortOrder 為 33。不一定是陣列索引或包含它的物件,只是數字。
謝謝
uj5u.com熱心網友回復:
- 使用
Object#values獲取陣列串列 - 使用
Array#flat,將二維陣列轉換為一個 - 使用
Array#reduce, 迭代此串列,同時更新max
const myObj = {
people: [ {firstname: 'Dave', lastName: 'Jones', sortOrder: 22}, {firstname: 'Jane', lastName: 'Smith', sortOrder: 11} ],
otherPeople: [ {firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33}, {firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12} ]
};
const maxSortOrder =
Object.values(myObj)
.flat()
.reduce((max, { sortOrder = 0 }) => sortOrder > max ? sortOrder : max, 0);
console.log(maxSortOrder);
uj5u.com熱心網友回復:
(我不得不稍微更正您的輸入資料:陣列不包括您顯示的索引號。)
最簡單的方法是將物件中的兩個陣列組合成一個串列,然后使用reduce找到最大值:
const myObj = {
people: [
{
firstname: 'Dave',
lastName: 'Jones',
sortOrder: 22
},
{
firstname: 'Jane',
lastName: 'Smith',
sortOrder: 11
}
],
otherPeople: [
{
firstname: 'Jen',
lastName: 'SomeLastName',
sortOrder: 33
},
{
firstname: 'ExampleFirstName',
lastName: 'ExampleLastName',
sortOrder: 12
}
]
};
let allPeople = [...myObj.people, ...myObj.otherPeople];
let max = allPeople.reduce((maxSort, person) => {
return Math.max(maxSort, person.sortOrder)
}, 0));
console.log(max)
uj5u.com熱心網友回復:
您可以按最高 sortOrder 對它們進行排序,然后取每個陣列中最高元素中的較高者:
const myObj = {
people: [{
firstname: 'Dave',
lastName: 'Jones',
sortOrder: 22
},
{
firstname: 'Jane',
lastName: 'Smith',
sortOrder: 11
}
],
otherPeople: [{
firstname: 'Jen',
lastName: 'SomeLastName',
sortOrder: 33
},
{
firstname: 'ExampleFirstName',
lastName: 'ExampleLastName',
sortOrder: 12
}
]
};
Object.values(myObj).forEach(peopleArray => {
peopleArray.sort((a, b) => b.sortOrder - a.sortOrder)
})
let maxValue = Math.max(myObj.people[0].sortOrder, myObj.otherPeople[0].sortOrder)
console.log(maxValue)
uj5u.com熱心網友回復:
const myObj = {
people: [
{firstname: 'Dave', lastName: 'Jones', sortOrder: 22},
{firstname: 'Jane', lastName: 'Smith', sortOrder: 11}
],
otherPeople: [
{firstname: 'Jen', lastName: 'SomeLastName', sortOrder: 33},
{firstname: 'ExampleFirstName', lastName: 'ExampleLastName', sortOrder: 12}
]};
let maxSortOrder = 0;
for (const value of Object.values(myObj)) {
maxSortOrder = value.reduce((acc, { sortOrder }) => sortOrder > acc ? sortOrder : acc, maxSortOrder);
};
console.log(maxSortOrder); //33
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