我正在構建一個測驗網站作為 React 的練習,并希望能夠通過按鈕更改問題。當我手動將 useState(0) 更改為 1 時,下一個物件會呈現。但我無法讓它與按鈕一起作業。當我單擊按鈕時,它會直接跳轉到警報訊息。
function GetMovies() {
useEffect(() => {
fetchItems();
}, []);
const [items, setItems] = useState({ options: [] });
const fetchItems = async () => {
const data = await fetch("http://localhost:5000/api/movies");
const items = await data.json();
//test
//console.log(items[currentQuestion]);
setItems(items[currentQuestion]);
};
const [currentQuestion, setCurrentQuestion] = useState(0);
//change question solution that dont work
const HandleAnswerButtonClick = () => {
const nextQuestion = setCurrentQuestion 1;
if (nextQuestion < items.length) {
setCurrentQuestion(nextQuestion);
} else {
alert("End of quiz");
}
setCurrentQuestion(nextQuestion);
};
return (
<div className="App">
<h1>Quiza</h1>
<div>
<span>Question 1</span>
</div>
<div>
<h3>Question: {items.description}</h3>
{items.options.map((c) => (
<button value={c.is_correct} key={c.text}>
{c.text}
</button>
))}
<div>
{//Next BUTTON}
<button onClick={() => HandleAnswerButtonClick()}>
Next question
</button>
</div>
{/* if-sats, om bild finns till fr?gan visas den, annars en class med display none */}
<div className="Q_pics">
{items.options.map((c) =>
!c.image ? (
<p className="Display_none">empty</p>
) : (
<img src={c.image} alt={c.text}></img>
)
)}
</div>
</div>
</div>
);
}
我的 API 中的貓鼬模式
const MovieSchema = mongoose.Schema(
{
category: { type: String, required: true },
description: { type: String, required: true },
image: {
type: String,
required: false,
},
options: [
{
text: {
type: String,
required: true,
},
is_correct: {
type: Boolean,
required: true,
default: false,
},
image: {
type: String,
required: false,
},
},
],
},
{ collection: "movies" }
);
uj5u.com熱心網友回復:
那是因為
const nextQuestion = setCurrentQuestion 1;
應該
const nextQuestion = currentQuestion 1;
哦,正如@Nick Parsons 在評論中提到的那樣,您也只在您的狀態中存盤第一個問題,因為fetchItems它只運行一次,并且您這樣做setItems(items[currentQuestion]);
你應該做類似的事情
function GetMovies() {
const [items, setItems] = useState([]);
const [currentQuestion, setCurrentQuestion] = useState(0);
const fetchItems = async () => {
const data = await fetch("http://localhost:5000/api/movies");
const items = await data.json();
//test
//console.log(items[currentQuestion]);
setItems(items);
};
//change question solution that dont work
const HandleAnswerButtonClick = () => {
const nextQuestion = currentQuestion 1;
if (nextQuestion < items.length) {
setCurrentQuestion(nextQuestion);
} else {
alert("End of quiz");
}
setCurrentQuestion(nextQuestion);
};
useEffect(() => {
fetchItems();
}, []);
const activeQuestion = items[currentQuestion];
return (
<div className="App">
<h1>Quiza</h1>
<div>
<span>Question {currentQuestion 1}</span>
</div>
<div>
<h3>Question: {activeQuestion && activeQuestion.description}</h3>
{activeQuestion && activeQuestion.options.map((c) => (
<button value={c.is_correct} key={c.text}>
{c.text}
</button>
))}
<div>
{//Next BUTTON}
<button onClick={() => HandleAnswerButtonClick()}>
Next question
</button>
</div>
{/* if-sats, om bild finns till fr?gan visas den, annars en class med display none */}
<div className="Q_pics">
{activeQuestion && activeQuestion.options.map((c) =>
!c.image ? (
<p className="Display_none">empty</p>
) : (
<img src={c.image} alt={c.text}></img>
)
)}
</div>
</div>
</div>
);
}
uj5u.com熱心網友回復:
代碼可能是這樣的:
const [items, setItems] = useState({ options: [] });
// currentIdx might be a better name
const [currentIdx, setCurrentIdx] = useState(0);
const fetchItems = async () => {
const data = await fetch("http://localhost:5000/api/movies");
const items = await data.json();
// save all data as Nick said. and items should be type of Data[];
setItems(items);
};
const HandleAnswerButtonClick = () => {
const nextQuestion = currentIdx 1;
if (nextQuestion < items.length) {
setCurrentIdx(nextQuestion);
} else {
alert("End of quiz");
}
};
// use displayItem for render
const displayItem = useMemo(() => items[currentIdx], [items, currentIdx]);
我認為你最好學會使用開發工具并觀察你的代碼的價值??
轉載請註明出處,本文鏈接:https://www.uj5u.com/qita/390095.html
標籤:javascript 数组 反应 接口 使用状态
