有沒有辦法縮短我的口袋妖怪游戲的傷害計算？我不斷重復代碼行

如您所見，當我計算造成的傷害時，我重復輸入口袋妖怪。只是想知道是否有更簡單的方法來撰寫此代碼。我想知道您是否可以使用某種表格，但不確定如何實作。為了以防萬一，我提供了大部分課程。

class Pokemon:
    def __init__(self, name, types, max_health, health, attack, defense):
        self.name = name
        self.types = types
        self.max_health = max_health
        self.health = health
        self.attack = attack
        self.defense = defense

    #Calculates the damage output depending on their attack and defense attributes
    def move(self, opponent):
        raw_dmg = 0
        choice = int(input("Choose your move: "))
        if choice == 1:
            raw_dmg = int((self.attack / opponent.defense) * 25)
        elif choice == 2:
            if accuracy(70):
                raw_dmg = int((self.attack / opponent.defense) * 40)
            else:
                raw_dmg = 0
        elif choice == 3:
            if accuracy(20):
                raw_dmg = int((self.attack / opponent.defense) * 200)
            else:
                raw_dmg = 0

        #Increases or decereases the damage depending on the type of both pokemon
        if self.types == "Fire":
            if opponent.types == "Water":
                raw_dmg = raw_dmg * 0.5
            elif opponent.types == "Grass":
                raw_dmg = raw_dmg * 2
        elif self.types == "Water":
            if opponent.types == "Grass":
                raw_dmg = raw_dmg * 0.5
            elif opponent.types == "Fire":
                raw_dmg = raw_dmg * 2
        elif self.types == "Grass":
            if opponent.types == "Fire":
                raw_dmg = raw_dmg * 0.5
            elif opponent.types == "Water":
                raw_dmg = raw_dmg * 2
        elif self.types == "Light":
            if opponent.types == "Dark":
                raw_dmg = raw_dmg * 2
        elif self.types == "Dark":
            if opponent.types == "Light":
                raw_dmg = raw_dmg * 2

        #The final damage is randomised by multiplying it by a value between 0.8 and 1.2
        final_dmg = round(raw_dmg * (random.randint(80, 120)) / 100)
        print(final_dmg)
        opponent.health -= final_dmg
        if opponent.health <= 0:
            opponent.health = 0
        return final_dmg

uj5u.com熱心網友回復：

只要有可能，最好將代碼轉換為資料：

前：

        if self.types == "Fire":
            if opponent.types == "Water":
                raw_dmg = raw_dmg * 0.5
            elif opponent.types == "Grass":
                raw_dmg = raw_dmg * 2
        elif self.types == "Water":
            if opponent.types == "Grass":
                raw_dmg = raw_dmg * 0.5
            elif opponent.types == "Fire":
                raw_dmg = raw_dmg * 2
        elif self.types == "Grass":
            if opponent.types == "Fire":
                raw_dmg = raw_dmg * 0.5
            elif opponent.types == "Water":
                raw_dmg = raw_dmg * 2
        elif self.types == "Light":
            if opponent.types == "Dark":
                raw_dmg = raw_dmg * 2
        elif self.types == "Dark":
            if opponent.types == "Light":
                raw_dmg = raw_dmg * 2

后：

# ahead of time in the global namespace
SUPER_EFFECTIVE = {
    ("Fire", "Grass"),
    ("Water", "Fire"),
    ...
}
NOT_VERY_EFFECTIVE = {
    ("Fire", "Water"),
    ("Water", "Grass"),
    ...
}

...

        # in the move function
        if (self.types, opponent.types) in SUPER_EFFECTIVE:
            raw_dmg *= 2.0
        elif (self.types, opponent.types) in NOT_VERY_EFFECTIVE:
            raw_dmg *= 0.5

uj5u.com熱心網友回復：

根據丹尼斯的回答，我會更進一步，制作一本字典，您可以在其中根據型別組合查找乘數。然后使用.get()，您可以使用默認值 1。這使得類中的代碼扁平而不是嵌套。

TYPE_MULTIPLIERS = {
    0.5: [
        ("Fire", "Water"),
        ("Water", "Grass"),
        ("Grass", "Fire"),
        ],
    2: [
        ("Fire", "Grass"),
        ("Water", "Fire"),
        ("Grass", "Water"),
        ("Light", "Dark"),
        ("Dark", "Light"),
        ],
    }

_MULTIPLIER_LOOKUP = {
    types: multiplier
    for multiplier, type_combos in TYPE_MULTIPLIERS.items()
    for types in type_combos}

# ... later

    raw_dmg *= _MULTIPLIER_LOOKUP.get((self.types, opponent.types), 1)

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