我正在撰寫處理影像并從串行埠發送影像顏色并顯示結果的python gui應用程式，但不幸的是我的gui凍結了。我嘗試使用 QApllication.processEvents，它可以作業，但我的程式速度很慢，速度對我來說非常重要，每一秒一次迭代都應該完成。這是我的代碼：
while self.knot <= knotter_width:
color_to_send = []
for i in range(1, number_of_knotter 1):
color_to_send.append(self.baft["knotters"][i][self.lay][self.knot])
# send color numbers
# receive color feedback
self.knot = self.knot 1
if self.knot > knotter_width:
break
self.config_write()
self.knotters_status() # gui update function
QCoreApplication.processEvents()
和knotters_status 函式：
def knotters_status(self):
try:
for i in range(number_of_knotter):
self.knotters_status_dict[i].deleteLater()
except:
pass
try:
self.baft
except:
self.status.setAlignment(Qt.Alignment(132))
status_gui_font_error = QFont("Arial", 43)
status_gui_font_error.setBold(True)
self.status.setFont(status_gui_font_error)
self.status.setText("???? ???? ??? ???? ???!")
return
self.knotters_status_dict = {}
# size calculation:
width_geo_start_point = 50
width_step = int((self.status_width - 50)/number_of_knotter)
self.each_knotters_sector_unit_height = int(self.status_height / 7)
knotters_status_font_size = int(self.each_knotters_sector_unit_height / 1.5)
knotters_status_font = QFont("Arial", knotters_status_font_size)
knotters_status_font.setBold(True)
for i in range(number_of_knotter):
self.knotters_status_dict[i] = QLabel(self.status)
self.knotters_status_dict[i].setGeometry((width_geo_start_point width_step * (number_of_knotter - i - 1)),
0,
width_step,
self.status_height)
self.knotters_status_dict[i].setStyleSheet("border: 1px solid black;"
"background-color: whitesmoke")
self.knotters_status_dict[i].setAlignment(Qt.Alignment(36))
self.knotters_status_dict[i].setFont(knotters_status_font)
color_number = self.baft["knotters"][i 1][self.lay][self.knot] 1
self.knotters_status_dict[i].setText("?????? {}\n??? {}\n??? {}\n??? {}".format(i,
self.lay,
self.knot,
color_number))
colors_width = width_step // 4
y = self.each_knotters_sector_unit_height * 4 self.each_knotters_sector_unit_height // 3
colors = {}
if self.lay != 1 and self.lay != self.baft["height"]:
if self.knot != 1 and self.knot != knotter_width:
for j in range(2):
colors[j] = {}
x = colors_width // 4
for k in range(1,-2,-1):
target_lay = self.lay - j
target_knot = self.knot k
colors[j][k] = QLabel(self.knotters_status_dict[i])
colors[j][k].setGeometry(x,
y,
colors_width,
self.each_knotters_sector_unit_height)
color_rgb = self.baft["color table"][self.baft["knotters"][i 1][target_lay][target_knot] 1]
colors[j][k].setStyleSheet("border: 1px solid black;"
"border-radius: 10px;"
"background-color: rgb({}, {}, {});".format \
(color_rgb[0],
color_rgb[1],
color_rgb[2]))
colors[j][k].show()
x = x colors_width colors_width // 4
y = y int(self.each_knotters_sector_unit_height * 4 / 3)
elif self.knot == 1:
pass
elif self.knot == knotter_width:
pass
elif self.lay == 1:
pass
elif self.lay == self.baft["height"]:
pass
self.knotters_status_dict[i].show()
經過我的研究，我發現了這個但也沒有作業：
class Worker(QObject):
progress = pyqtSignal(int)
gui_update = pyqtSignal()
finish = pyqtSignal(bool)
ex = pyqtSignal()
@pyqtSlot(int, int, dict)
def run(self, knot, lay, baft):
# send finish order
# recieve finish feedback
while knot <= knotter_width:
color_to_send = []
for i in range(1, number_of_knotter 1):
color_to_send.append(baft["knotters"][i][lay][knot])
# send color numbers
# receive color feedback
if knot < knotter_width:
knot = knot 1
else:
break
self.progress.emit(knot)
self.gui_update.emit()
self.finish.emit(True)
# send finish order
#reveive finish feedback
self.ex.emit()
這設定了執行緒：
self.thrd = QThread()
self.worker = Worker()
self.worker.moveToThread(self.thrd)
self.thrd.started.connect(lambda: self.worker.run(self.knot, self.lay, self.baft))
self.worker.progress.connect(self.progress)
self.worker.gui_update.connect(self.knotters_status)
self.worker.finish.connect(self.finished)
self.worker.ex.connect(self.thrd.quit)
self.worker.ex.connect(self.worker.deleteLater)
self.thrd.finished.connect(self.thrd.deleteLater)
self.thrd.start()
uj5u.com熱心網友回復：
經過幾天的研究，我發現了這個解決方案：首先，您必須撰寫類并從 QThread 類繼承，然后使用信號和插槽重新實作 run 方法，然后您從該類創建物件，然后您應該呼叫processEvents()參考您的 QApplication 物件的方法。在這種情況下，它不會導致速度變慢，并且非常適合 mopre 細節，您可以參考我的另一個問題和答案，您可以單擊此處
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