假設我有這樣的資料框:
id,month,price
1,2021-04-31,9
1,2021-01-31,5
1,2021-02-31,6
1,2021-03-31,8
所以對于每個相同的ID我想獲取price當前行month-1的總和-2
例如對于 row 1,march,8,我將5 6=11在新列中獲得輸出,因為對于當前三月行過去兩個月是jan和feb
ids主要資料中也會有其他的
uj5u.com熱心網友回復:
將名稱轉換為月份數字,然后將其用于在按運行 summonth磁區的 Window 中進行排序:id
from pyspark.sql import functions as F, Window
df = spark.createDataFrame([
(1, "apr", 9), (1, "jan", 5),
(1, "feb", 6), (1, "march", 8)
], ["id", "month", "price"])
# handle both full and short textual representation of month names
month_number = F.when(F.length("month") == 3, F.month(F.to_date(F.col("month"), "MMM"))) \
.otherwise(F.month(F.to_date(F.col("month"), "MMMM")))
w = Window.partitionBy("id").orderBy(month_number).rangeBetween(-2, -1)
df.withColumn("price_sum", F.sum("price").over(w)).show()
# --- ----- ----- ---------
#| id|month|price|price_sum|
# --- ----- ----- ---------
#| 1| jan| 5| null|
#| 1| feb| 6| 5|
#| 1|march| 8| 11|
#| 1| apr| 9| 14|
# --- ----- ----- ---------
對于您更新的問題,您可以將日期截斷為月份單位,然后使用范圍介于interval -2 months和之間的視窗interval -1 months:
df = spark.createDataFrame([
(1, "2021-04-30", 9), (1, "2021-01-31", 5),
(1, "2021-02-28", 6), (1, "2021-03-31", 8)
], ["id", "month", "price"])
df.withColumn(
"date",
F.date_trunc("month", F.col("month"))
).withColumn(
"price_sum",
F.expr("""sum(price) over(partition by id order by date
range between interval 2 months preceding
and interval 1 months preceding)
""")
).drop("date").show()
uj5u.com熱心網友回復:
使用視窗函式對價格、按月磁區(數字)求和,并使用 ROWS 獲取前兩行。
from pyspark.sql import SparkSession
spark = SparkSession.builder.getOrCreate()
df = spark.read.option("header",True).csv("path/to/file") # Assuming file is csv
df.createOrReplaceTempView('df')
df1 = spark.sql("""
SELECT id,month,price,
CASE
WHEN month = 'jan' THEN 1
WHEN month = 'feb' THEN 2
.
.
.
else 12
END AS month_num
FROM df
""")
df1.createOrReplaceTempView('df1')
spark.sql("""
SELECT id, month, price,
SUM(price) OVER (PARTITION BY id ORDER BY month_num ROWS 2 PRECEDING) AS price_sum
FROM df1
""").show()
添加到第二個查詢
WHERE month_num NOT IN (1,2)
如果您想要 1 月和 2 月的 price_sum 0。
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