也就是他按下按鈕，1號功能啟動，再次按下，2號功能啟動。2號功能一次又一次按下，以此類推……單個MDFloatingActionButton怎么辦？
from kivymd.app import MDApp
from kivy.lang import Builder
from kivymd.uix.button.button import MDFloatingActionButton
KV = '''
MDFloatLayout:
MDFloatingActionButton:
icon: "flashlight"
pos_hint: {'center_x': .5, 'center_y': .5}
on_release: app.foo1() and app.foo2()
'''
class Test(MDApp):
def build(self):
screen = Builder.load_string(KV)
return screen
def foo1(self):
print("foo1")
def foo2(self):
print("foo2")
Test().run()
uj5u.com熱心網友回復：
MDFloatingActionButton:
icon: "flashlight"
pos_hint: {'center_x': .5, 'center_y': .5}
on_release:
app.foo1()
app.foo2()
應該這樣做
編輯：對不起，我好像誤解了你的問題。這是你應該怎么做
from kivymd.app import MDApp
from kivy.lang import Builder
KV = '''
MDFloatLayout:
MDFloatingActionButton:
icon: "flashlight"
pos_hint: {'center_x': .5, 'center_y': .5}
on_release: app.button_on_release()
'''
class Test(MDApp):
release_count = 0
def build(self):
screen = Builder.load_string(KV)
return screen
def button_on_release(self):
if self.release_count == 0:
self.foo1()
self.release_count = 1
return
if self.release_count == 1:
self.foo2()
self.release_count = 0
return
def foo1(self):
print("foo1")
def foo2(self):
print("foo2")
Test().run()
轉載請註明出處，本文鏈接：https://www.uj5u.com/qita/425238.html
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