我查詢要保存到 SQL Server 2016 表的 API 和 JSON 輸出。這是我模擬轉換 JSON 輸出的方式：
當我運行這個：
DECLARE @J NVARCHAR(MAX) = '{"c":[4.935,4.935,4.9374,4.935,4.94],"t":[1643998980,1643999040,1643999100,1643999160,1643999220],"v":[1979,87494,9980,4382,17713]}';
SELECT [key] as jkey, value as c
FROM OPENJSON(@j, '$.c');
我明白了：
jkey,c
0,4.935
1,4.935
2,4.9374
3,4.935
4,4.94
但我希望這樣：
jkey,c,t,v
0,4.935,1643998980,1979
1,4.935,1643999040,87494
2,4.9374,1643999100,9980
3,4.935,1643999160,4382
4,4.94,1643999220,17713
我花了幾個小時，我無法弄清楚。請幫忙。
uj5u.com熱心網友回復：
只需加入其他鍵的鍵即可。
DECLARE @J NVARCHAR(MAX) = '{"c":[4.935,4.935,4.9374,4.935,4.94],"t":[1643998980,1643999040,1643999100,1643999160,1643999220],"v":[1979,87494,9980,4382,17713]}'; SELECT c.[key] as jkey, c.value as c, t.value as t, v.value as v FROM OPENJSON(@j, '$.c') c LEFT JOIN OPENJSON(@j, '$.t') t ON t.[key] = c.[key] LEFT JOIN OPENJSON(@j, '$.v') v ON v.[key] = c.[key] ORDER BY jkey;
鍵 C 噸 v 0 4.935 1643998980 1979 1 4.935 1643999040 87494 2 4.9374 1643999100 9980 3 4.935 1643999160 4382 4 4.94 1643999220 17713
db<>在這里擺弄
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