Python3：我的代碼假設從該檔案中列印一個名稱和一個分數，但它會列印兩次名稱和兩次分數。為什么？

這是作業：

• 第一個程式將讀取每個球員的姓名和高爾夫分數作為鍵盤輸入，然后將這些作為記錄保存在名為 golf.txt 的檔案中。（每條記錄都有一個玩家姓名欄位和一個玩家得分欄位。）
• 第二個程式從 golf.txt 檔案中讀取記錄并顯示它們。

到目前為止，這是我的代碼：

def main():
    Continue = 'yes'
    golf_file = open('golf.txt', 'a')
    while Continue == 'yes':
        player_name = input("Input the player's name: ")
        player_score = input("Input the player's score: ")
        golf_file.write(player_name   "\n")
        golf_file.write(str(player_score)   "\n")
        Continue = input("Would you like to continue? [yes]: ")
    display_file = input("Would you like to display the records from the golf.txt? [yes]: ")
    golf_file.close()
    if(display_file == 'yes'):
            displayfile()

def displayfile():
    golf_file = open('golf.txt', 'r')

    for line in golf_file:
        print("The score of this person is: ",line)
        print("The name of this person is: ",line)
    golf_file.close()

main()

當名稱/分數列印時，它看起來像這樣：

高爾夫.txt：

uj5u.com熱心網友回復：

您正在閱讀一行（包含名稱），并將其列印為名稱和樂譜。然后你閱讀包含樂譜的下一行）并再次將其列印為名稱和樂譜。

您想交替將一行視為名稱或樂譜，例如

def displayfile():
    with open('golf.txt', 'r') as golf_file:

        for name in golf_file:
            print("The name of this person is: ", name)
            score = next(golf_file)
            print("The score of this person is: ", score)

因為golf_file是它自己的迭代器，next所以在回圈體中呼叫會使檔案指標前進一行，因此回圈總是通過讀取名稱行來恢復。

更對稱的東西可能是

def displayfile():
    with open('golf.txt', 'r') as golf_file:
        while True:
            try:
                name = next(golf_file)
                score = next(golf_file)
            except StopIteration:
                break
            print("The name of this person is: ", name)
            print("The score of this person is: ", score)

然而，更簡單的方法是將每個名字和分數寫在一行上。

def main():
    with open('golf.txt', 'a') as golf_file:
        while True:
            player_name = input("Input the player's name: ")
            player_score = input("Input the player's score: ")
            golf_file.write(f"{player_name}\t{player_score}\n")

            continue = input("Would you like to continue? [yes]: ")
            if continue != 'yes':
               break
    display_file = input("Would you like to display the records from the golf.txt? [yes]: ")
    if display_file == 'yes':
        displayfile()


def displayfile():
    with open('golf.txt', 'r') as golf_file:

        for line in golf_file:
            name, score = line.strip().split('\t')
            print("The score of this person is: ", name)
            print("The name of this person is: ", score)

main()

uj5u.com熱心網友回復：

在一行中，您列印出分數和名稱。例如，第 1 行是sam：

print("The name of this person is: ",line),

所以它列印出來"The name of this person is: sam"。

print("The score of this person is: ",line)

所以它列印出來"The score of this person is: sam"。

我認為你應該添加一個變數來計算像line_number = 1.

如果line_number % 2 == 1（該行應該是名稱）則：

print("The name of this person is: ", line)

如果line_number % 2 == 0（那條線應該是一個分數）那么：

print("The name of this person is: ", line)

在一個回圈之后，該行應該加 1，所以你應該寫： line_number = 1

畢竟，您的代碼如下所示：

def main():
    Continue = 'yes'
    golf_file = open('golf.txt', 'a')
    while Continue == 'yes':
        player_name = input("Input the player's name: ")
        player_score = input("Input the player's score: ")
        golf_file.write(player_name   "\n")
        golf_file.write(str(player_score)   "\n")
        Continue = input("Would you like to continue? [yes]: ")
    display_file = input("Would you like to display the records from the golf.txt? [yes]: ")
    golf_file.close()
    if(display_file == 'yes'):
            displayfile()

def displayfile():
    golf_file = open('golf.txt', 'r')

    line_number = 1
    for line in golf_file:
        if line_number % 2 == 0:
            print("The score of this person is: ",line)

        if line_number % 2 == 1:
            print("The name of this person is: ",line)

        line_number  = 1
    golf_file.close()

main()

那么問題就解決了！恭喜！

標籤：Python

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