我有一個網頁，其中每個視圖都被計數并增加 3，而它打算增加 1
這是我的觀點.py
from django.views.generic import ListView, DetailView
class MovieDetail(DetailView):
model = Movie
def get_object(self):
object = super(MovieDetail, self).get_object()
object.views_count = 1
object.save()
return object
def get_context_data(self, **kwargs):
context = super(MovieDetail, self).get_context_data(**kwargs)
context['links'] = MovieLink.objects.filter(movie=self.get_object())
context['related_movies'] = Movie.objects.filter(category=self.get_object().category)
return context
html
<section class="movie">
<img src="{{object.image.url}}">
<ul>
<li>{{object}}</li>
<li>{{object.description}}</li>
<li><a href="genre.html">Adventure</a>, <a href="genre.html">Drama</a>, <a href="genre.html">Romance</a></li>
<li><a href="">{{object.cast}}</a></li>
<li><i class="fa fa-eye" id="eye"></i> {{object.views_count}}</li>
</ul>
</section>
計劃增加 1 但不遵循該邏輯..這里出了什么問題？
uj5u.com熱心網友回復：
get_object()處理視圖時可能會多次呼叫。例如，您可以將代碼移動到render_to_response()方法中。還要確保使用F() 運算式增加資料庫欄位。
from django.db.models import F
class MovieDetail(DetailView):
model = Movie
def render_to_response(self, *args, **kwargs):
self.object.views_count = F('views_count') 1
self.object.save()
return super().render_to_response(*args, **kwargs)
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