是否可以定義一個函式，它將任何列舉值作為引數，然后迭代型別？像這樣的偽代碼：
#[derive(Display)]
enum Difficulty {
Easy,
Middle,
Hard,
}
fn enum_as_radio_select<T: Enum Display>(selected: T) {
for enum_value in T::iter() {
let is_selected = enum_value == selected;
let text = enum_value.to_string();
add_radio_button(is_selected, text);
}
}
enum_as_radio_select(Difficulty::Easy);
uj5u.com熱心網友回復：
strum箱子有這個：（注意#[derive(EnumIter)]您需要激活該derive功能）：
#[derive(strum::EnumIter, Display, PartialEq, Eq)]
enum Difficulty {
Easy,
Middle,
Hard,
}
fn enum_as_radio_select<T: Display strum::IntoEnumIterator PartialEq>(selected: T) {
for enum_value in T::iter() {
let is_selected = enum_value == selected;
let text = enum_value.to_string();
add_radio_button(is_selected, text);
}
}
enum_as_radio_select(Difficulty::Easy);
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