查找年份之間的分鐘數

你能檢查我的代碼嗎？我認為某處有問題。

import datetime
this_year = datetime.datetime.today().year


def age_in_minutes(b_year: int):
    d1 = datetime.datetime.strptime(f'{this_year}', '%Y')
    d2 = datetime.datetime.strptime(f'{b_year}', '%Y')
    age = (d1-d2).days * 24 * 60
    return f"{age:,}"


while True:
    birth_year = input("Enter you birth year: ")
    try:
        if int(birth_year) == this_year:
            print("Please enter year less than this year...")
        elif int(birth_year) > this_year:
            print("Please enter year less than this year...")
        elif len(birth_year) < 4 or len(birth_year) > 5:
            print("PLease enter a valid year...")
        elif int(birth_year) <= 1900:
            print("Please enter a year after 1900...")
        else:
            minutes_old = age_in_minutes(int(birth_year))
            print(f"You are {minutes_old} minutes old.")
            break
    except ValueError:
        print("Please enter in a year format: ")

我正在應對挑戰。它說如果我輸入 1930，我應該得到“ 48,355,200 ”。但我得到“ 48,388,320 ”。我是 Python 新手。

uj5u.com熱心網友回復：

You haven't calculated leap year. You can follow this:

import datetime

this_year = datetime.datetime.today().year


def age_in_minutes(b_year: int):
    leap_year = 0
    non_leap_year = 0

    for year in range(b_year, this_year 1):
        if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
            leap_year  = 1
        else:
            non_leap_year  = 1
    
    leap_year_in_days = leap_year * 366
    non_leap_year_in_days = non_leap_year * 365
    age = (leap_year_in_days   non_leap_year_in_days) * 24 * 60
    return f"{age:,}"


while True:
    birth_year = input("Enter you birth year: ")
    try:
        if int(birth_year) == this_year:
            print("Please enter year less than this year...")
        elif int(birth_year) > this_year:
            print("Please enter year less than this year...")
        elif len(birth_year) < 4 or len(birth_year) > 5:
            print("PLease enter a valid year...")
        elif int(birth_year) <= 1900:
            print("Please enter a year after 1900...")
        else:
            minutes_old = age_in_minutes(int(birth_year))
            print(f"You are {minutes_old} minutes old.")
            break
    except ValueError:
        print("Please enter in a year format: ")

uj5u.com熱心網友回復：

你可以試試這段代碼，我在 2021 年的某個地方找到了它，但我不知道來源

current_year = 2022
year = int(input("Please enter a year: "))

if year == current_year:
    print("There are 0 minutes from", year, "to present.")
elif year < current_year:
    print("There are", (current_year - year) * 525600, "minutes from", year, "to present.")
else:
    print("There are", (year - current_year) * 525600, "minutes from present to", year)

uj5u.com熱心網友回復：

嘗試這個：

import datetime
this_year = datetime.datetime.today().year

print(this_year)
def age_in_minutes(b_year: int):
    d1 = datetime.datetime.strptime(f'{this_year}', '%Y')
    d2 = datetime.datetime.strptime(f'{b_year}', '%Y')
    age = (d1-d2).days * 24 * 60
    return f"{age:,}"


while True:
    birth_year = int(input("Enter you birth year: "))
    try:
        if birth_year == this_year:
            print("Please enter year less than this year...")
        elif birth_year > this_year:
            print("Please enter year less than this year...")
        elif len(str(birth_year)) < 4 or len(str(birth_year)) > 5:
            print("PLease enter a valid year...")
        elif birth_year <= 1900:
            print("Please enter a year after 1900...")
        else:
            minutes_old = age_in_minutes(birth_year)
            print(f"You are {minutes_old} minutes old.")
            break
    except ValueError:
        print("Please enter in a year format: ")

輸出：

Enter you birth year: 1930
You are 48,388,320 minutes old.

我沒有做任何例外，但改變你的型別轉換，它可以給我一個想要的結果。

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