代碼
current_number = 0
while current_number <10:
current_number += 1
if current_number % 2 ==0:
continue
print(current_number)
同理輸入break也是,小白一枚,請解答。
uj5u.com熱心網友回復:
你的print(current_number)也屬于if陳述句的縮進范圍之內,而前面的陳述句是continue, 或者break,
那意味著print(current_number)是不可到達的代碼!
uj5u.com熱心網友回復:
current_number = 0
while current_number <10:
current_number += 1
if current_number % 2 ==0:
print(current_number)
continue
轉載請註明出處,本文鏈接:https://www.uj5u.com/qita/82712.html
下一篇:pycharm我用pymysql.connect的conn能有cursor提示,但是用連接池DBUtils獲取的conn就沒有.cursor提示
