如下，python發郵件時，把收件人主知member串列里，然后用for回圈挨個的取出挨個的發，
第一個郵件是[email protected]收到，
但是第二個則是a收到，b也收到
第三個則是a收到，b收到，c也收到，
這是為什么呢？
我本意是希望a收到一個郵件，b收到一個，c收到一個的
try:
member=["[email protected]","[email protected]","[email protected]"]
for to_mail in member:
a=a+1
subject=str(a)+'-Python郵件-'+nowtime
message['To']=Header(to_mail)
message['Subject']=Header(subject,'utf-8')#郵件標題
stmp.sendmail(from_addr, to_mail, message.as_string())
# print (subject,to_mail)
print (to_mail+','+str(a)+'-郵件發送成功',nowtime)
time.sleep(0.1)
uj5u.com熱心網友回復：
不需要遍歷的，message['To']=Header(to_mail)，這里的to_mail接收的就是一個串列，你全部給進來就行了，不需要遍歷，你debug一下Header引數型別就能看出來uj5u.com熱心網友回復：
member=["[email protected]","[email protected]","[email protected]"]
subject=str(a)+'-Python郵件-'+nowtime
message['To']=Header(member)
message['Subject']=Header(subject,'utf-8')#郵件標題
stmp.sendmail(from_addr, to_mail, message.as_string())
print (to_mail+','+str(a)+'-郵件發送成功',nowtime)
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