假設您有一個資料框,并且您想通過添加新pattern_name列來過濾掉逐行模式 。列
的型別pattern_name應該是一個陣列,因為每一行都可能匹配多個模式。
# Input
df = spark.createDataFrame(
[(1, 21, 'A foo text'),
(2, 42, 'A foo'),
(2, 42, 'A foobar text'),
(2, 42, 'barz'),],
['id_1', 'id_2', 'text']
)
# Patterns:
# pattern_foo_1: id_1 = 1, id_2 = 21, text.rlike('foo')
# pattern_foo_2: id_1 = 2, id_2 = 42, text.rlike('foo')
# pattern_foobar: id_1 = 2, id_2 = 42, text.rlike('foobar')
# Desired output: (null can also be empty string, doesn't matter)
------ ------ ---------------- ------------------------------------
| id_1| id_2| text| pattern_name|
------ ------ ---------------- ------------------------------------
| 1| 21| 'A foo text'| ['pattern_foo_1', ]|
| 2| 42| 'A foo'| ['pattern_foo_2', ]|
| 2| 42| 'A foobar text'| ['pattern_foo_2', 'pattern_foobar']|
| 2| 42| 'barz'| null|
------ ------ ---------------- ------------------------------------
由于輸入非常大,您如何以有效的方式(無 udf)執行此操作?
過去,我的 df 每行最多只有一個匹配項,所以我使用了when函式(下面的示例)。但是,如果每行有多個匹配項,則這不起作用,您需要一個陣列。
pattern_name_col = None
for pattern in pattern_list:
if pattern_name_col is None:
# pseudocode example
pattern_name_col = when(
(col('id_1') == 1) & (col('id_2') == 21)
& (col('text').rlike('foo')),
'pattern_foo_1')
else:
pattern_name_col = pattern_name_col.when(..., ...)
df = df.withColumn('pattern_name', pattern_name_col).filter(col('pattern_name').isNotNull())
uj5u.com熱心網友回復:
您可以將patterns串列定義為:
patterns = [
(1, 21, "foo", "pattern_foo_1"), # (id_1, id_2, pattern, pattern_name)
(2, 42, "foo", "pattern_foo_2"),
(2, 42, "foobar", "pattern_foobar"),
]
然后使用array具有串列理解的函式,when您可以獲得模式名稱的串列列:
import pyspark.sql.functions as F
df1 = df.withColumn(
"pattern_name",
F.array(*[
F.when((F.col("id_1") == p[0]) & (F.col("id_2") == p[1]) & F.col("text").rlike(p[2]), p[3])
for p in patterns
])
).withColumn(
"pattern_name",
F.expr("filter(pattern_name, x -> x is not null)")
)
df1.show(truncate=False)
# ---- ---- ------------- -------------------------------
#|id_1|id_2|text |pattern_name |
# ---- ---- ------------- -------------------------------
#|1 |21 |A foo text |[pattern_foo_1] |
#|2 |42 |A foo |[pattern_foo_2] |
#|2 |42 |A foobar text|[pattern_foo_2, pattern_foobar]|
#|2 |42 |barz |[] |
# ---- ---- ------------- -------------------------------
您還可以patterns_df從上面的串列中創建一個資料框,然后使用 join 后跟 goupby collect_list:
patterns_df = spark.createDataFrame(patterns, ["id_1", "id_2", "pattern", "pattern_name"])
df1 = df.alias("df").join(
patterns_df.alias("p"),
F.expr("df.id_1 = p.id_1 and df.id_2 = p.id_2 and df.text rlike p.pattern")
).groupBy("df.id_1", "df.id_2", "text").agg(
F.collect_list("pattern_name").alias("pattern_name")
)
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