使用二分法找到 f(x) = sqrt(x) - cos(x) 的 p3，我在紙上得到了正確的答案 p3 = .625
我在轉換問題并使用 Jupyter notebook 解決問題時遇到了麻煩。有小費嗎？
Jupyter 筆記本代碼
uj5u.com熱心網友回復：
0.625是逼近程序中的第三次猜測，所以for回圈應該在第四次迭代之前完成，代碼應該如下。
import math
##problem statement
#finding a root of f(x) = sqrt(x)-cos(x) between the interval [0,1]
#f(0) = -1 f(1) = 0.45969.. so there is at least one root between the interval [0,1]
a = 0
b = 1
maxIt = 100
negative_result = math.sqrt(a) - math.cos(a)
positive_result = math.sqrt(b) - math.cos(b)
for i in range(maxIt):
if i == 3:
print("answer is: ", guess)
break
guess = (a b)/2
guess_result = math.sqrt(guess) - math.cos(guess)
if guess_result*negative_result >= 0:
a = guess
else:
b = guess
輸出是
0.625
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標籤：数学 jupyter-笔记本