SELECT SUM(COUNT(HR.ID), COUNT(HRWX.ID)) AS 總計
FROM HR, HRWX;
運行提示用于函式引數的個數不對 在查詢運算式‘SUM(COUNT(HR.ID), COUNT(HRWX.ID)) ’
uj5u.com熱心網友回復:
SELECT COUNT(1) FROM(SELECT ID FROM HR
UNION ALL
SELECT ID FROM HRWX) AA
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