select * from (
select a.id as aa,b.id as bb from
(
select id from temp.ods_ecs
) a
left join
(
select id from temp.ftp_ecs where dt='2021-01-11'
) b
on a.id=b.id
) c where bb is null
如何獲取a.id比b.id少了那幾條資料資訊,求詳解
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標籤:疑難問題
