我想存檔，我洗掉了每個專案中的所有重復專案。
所以我去一個帶有專案的div：
<div class="each">
<div>Test2</div>
<div>Test</div>
<div>Test</div>
</div>
<div class="each">
<div>Test2</div>
<div>Test</div>
<div>Test</div>
</div>
到目前為止我的 Jquery：
$('.dropPlace').each(function(index){
console.log($(this).text());
});
所以我想檢查每個 div是否存在兩個重復的文本。并且只在div.
所以結果是這樣的：
<div class="each">
<div>Test2</div>
</div>
<div class="each">
<div>Test2</div>
</div>
uj5u.com熱心網友回復：
這是一個作業演示。
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script>
$(document).ready(function () {
var map = {};
$("#remove").click(function () {
// use an object as map
var map = {};
$(".dropPlace").each(function () {
var value = $(this).text();
if (map[value] == null) {
map[value] = true;
} else {
$(this).remove();
}
});
});
});
</script>
</head>
<body>
<div class="each">
<div class="dropPlace">Test2</div>
<div class="dropPlace">Test</div>
<div class="dropPlace">Test</div>
</div>
<div class="each">
<div class="dropPlace">Test2</div>
<div class="dropPlace">Test</div>
<div class="dropPlace">Test</div>
</div>
<button id="remove">remove</button
</body>
</html>uj5u.com熱心網友回復：
下面肯定可以優化，但它會給出你要求的結果：
<div class="each">
<div>Test2</div>
</div>
<div class="each">
<div>Test2</div>
</div>
$('.each').each(function() {
const textAr = [];
let parent = $(this);
parent.children('div').each(function() {
let _this = $(this), elText = _this.text();
if(textAr.includes(elText)) {
parent.children('div').each(function() {
let _child = $(this);
if(_child.text() == elText){
_child.remove();
}
})
}
else textAr.push(elText)
});
});.each {
margin-bottom: 1em;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="each">
<div>Test2</div>
<div>Test</div>
<div>Test</div>
</div>
<div class="each">
<div>Test2</div>
<div>Test</div>
<div>Test</div>
</div>轉載請註明出處，本文鏈接：https://www.uj5u.com/shujuku/339755.html
標籤：javascript 查询 每个