如何在螢屏上獲取由tkinter包創建的復選框的坐標

我使用 tkinter 包中提供的 Checkbox 類創建了一個具有 3 個復選框的圖形用戶界面。我想檢索每個復選框的螢屏坐標。我一直在嘗試使用 pyautogui.position() 來檢索坐標。但是，這些值似乎是錯誤的，因為當我使用 pyautogui 引??擎的這些坐標單擊框時，它沒有單擊。此外，似乎包含復選框的視窗不允許我在除錯時選中這些框。有什么其他可能的方法可以解決這些問題？

from tkinter import *
import SpeechToDictation as Std
import pyautogui
import time


def speech_to_dictation():
    speech_inst = Std.SpeechToDictation()
    dictation.append(speech_inst.read_audio())


def user_speech_to_dictation():
    main_window = Tk()
    button = Button(text='Recording')
    button.pack()
    # have a while true at here so that when the function executes, it quits out of the loop
    button.config(command=speech_to_dictation)
    main_window.mainloop()


class Test(Frame):
    def __init__(self, parent=None, picks=[]):
        Frame.__init__(self, parent)
        self.vars = []
        self.checkboxes = []
        Label(self, text='Lab Works').grid(row=0, padx=10, pady=10)
        i = 1
        for pick in picks:
            var = IntVar()
            chk = Checkbutton(self, text=pick, variable=var)
            chk.grid(row=i, pady=4, padx=10)
            self.vars.append(var)
            self.checkboxes.append(chk)
            i  = 1

    def state(self):
        return map((lambda var: var.get()), self.vars)


def full_screen(window):
    width = window.winfo_screenwidth()
    height = window.winfo_screenheight()
    window.geometry("%dx%d" % (width, height))


def allstates():
    print(list(lng.state()))


def make_test(window):
    full_screen(window=root)
    window.grid(row=1, column=0)
    Button(root, text='Quit', command=root.quit).grid(row=10, padx=10, pady=10)
    Button(root, text='Peek', command=allstates).grid(row=12, padx=10, pady=10)


if __name__ == '__main__':
    # store dictation at dictation[]
    dictation = []
    user_speech_to_dictation()
    is_string_complete = dictation[0]['text'][:8]
    if is_string_complete == 'complete':
        start_time = time.time()  # returns number of seconds passed since epoch
        max_loop_time = 1  # 1 seconds

        while True:
            if (time.time() - start_time) >= max_loop_time:
                root = Tk()
                lng = Test(root, ['Blood Count', 'Lipid Panel', 'Hemoglobin A1C'])
                make_test(window=lng)
                root.state('zoomed')
                root.update()
                x_position, y_position = pyautogui.position()
                print(x_position, y_position)
                max_loop_time = time.time() - start_time   max_loop_time
                # Coordinate of each boxes: they seem wrong
                locations = [(53, 158), (84, 228), (36, 302)]
                blood_count_string = dictation[0]['text'][9:]
                if blood_count_string == 'blood count':
                    x_coordinate = locations[0][0]
                    y_coordinate = locations[0][1]
                    pyautogui.click(x_coordinate, y_coordinate)
                    allstates()
                root.destroy()

            # quit the program after the window is destroyed
            if max_loop_time > 2:
                break

uj5u.com熱心網友回復：

以下是如何獲取坐標并單擊復選按鈕的快速示例（只需使用.winfo_rootx()和.winfo_rooty()）：

import tkinter as tk
import pyautogui as pag


def click_btn():
    x = check_btn.winfo_rootx()
    y = check_btn.winfo_rooty()
    pag.click(x, y)


root = tk.Tk()

check_btn = tk.Checkbutton(root, text='This will be clicked in 3 seconds')
check_btn.pack()

root.after(3 * 1000, click_btn)

root.mainloop()

標籤：Python 特金特 pyautogui

上一篇：將Tkinter按鈕命令的結果用于另一個Tkinter命令函式

下一篇：排序后的PythonTreeview交替行著色