當非管理員用戶在管理面板中登錄時，如何隱藏一些導航欄頁面？

我所做的是把所有這些

索引.php

<?php
include('includes/navbar.php');
?>

<!-- Main Content  -->

<?php
include('includes/footer.php');
?>

頁面2.php

<?php
include('includes/navbar.php');
?>

<!-- Main Content  -->

<?php
include('includes/footer.php');
?>

頁面3.php

<?php
include('includes/navbar.php');
?>

<!-- Main Content  -->

<?php
include('includes/footer.php');
?>

第4頁.php

<?php
include('includes/navbar.php');
?>

<!-- Main Content  -->

<?php
include('includes/footer.php');
?>

第5頁.php

<?php
include('includes/navbar.php');
?>

<!-- Main Content  -->

<?php
include('includes/footer.php');
?>

code.php 這是驗證用戶是管理員用戶還是非管理員用戶的代碼 !password_verify 用于驗證密碼和哈希密碼。

if(isset($_POST['login_btn']))
{
    $email_login = $_POST['emaill']; 
    $password_login = $_POST['passwordd']; 
    
    $query = "SELECT * FROM register WHERE email='$email_login' LIMIT 1";
    $query_run = mysqli_query($connection, $query);
    $password = "SELECT password FROM register WHERE email='$email_login'";
    $usertypes = mysqli_fetch_array($query_run);

   if($usertypes['usertype'] == "admin")
   {
    if(!password_verify($password_login, $password))
    {   
        $_SESSION['username'] = $usertypes['username'];
        header('Location: index.php');
    }
    else
    {
         $_SESSION['status'] = "Email / Password is Invalid";
         header('Location: login.php');
    }
   } 
   else if  ($usertypes['usertype'] == "user")
   {
    if(!password_verify($password_login, $password)){   
        $_SESSION['username'] = $usertypes['username'];
        header('Location: index2.php');
    }
    else
    {
         $_SESSION['status'] = "Email / Password is Invalid";
         header('Location: login.php');
    }
   }
}

UPDATE: I've already found a solution to the problem... Just put all the list items tag<li></li> inside this php elseif if you want to display a specific navbar list when an Admin user is logged in but want to hide them in a non-admin one.

<?php if($_SESSION['TYPE'] == 'admin'): ?>

<li class="nav-item">
    <a class="nav-link" href="PageForAdmin.php">
        <i class="fas fa-user" style="font-size: 20px;"></i>
        <span>Page For Admin</span></a>
</li>

<?php endif;  ?>

uj5u.com熱心網友回復：

使用if else回圈 For Laravel

@if(Auth::user()->user_role == "role")
// Show page 1
@else
// show page 2
@endif

為你

<?php

if ($user->role == 'admin'){
<li class="nav-item">
    <a class="nav-link" href="page1.php">
        <i class="fas fa-fw fa-tachometer-alt"></i>
        <span>Page1</span></a>
</li>

   
 }else {
 <li class="nav-item">
    <a class="nav-link" href="page.php">
        <i class="fas fa-fw fa-tachometer-alt"></i>
        <span>Page2</span></a>
</li>

 }

?>

可能是代碼沒有編譯

<?php

if ($user->role == "admin"){

如果您使用數字，則

<?php

if ($user->role == 1){

注意：這是您可以使用的示例。我沒有測驗過。在條件下使用您想要的使用方式role或用戶型別if

<?php
    
    if ($usertype->username == "admin){

5 頁示例

<?php

if ($user->role == 'admin'){
<li class="nav-item">
    <a class="nav-link" href="page1.php">
        <i class="fas fa-fw fa-tachometer-alt"></i>
        <span>Page1</span></a>
</li>

   
 }else if ($user->role == 'author'){
 <li class="nav-item">
    <a class="nav-link" href="page.php">
        <i class="fas fa-fw fa-tachometer-alt"></i>
        <span>Page2</span></a>
</li>

 

 }else if ($user->role == 'editor'){
 <li class="nav-item">
    <a class="nav-link" href="page.php">
        <i class="fas fa-fw fa-tachometer-alt"></i>
        <span>Page3</span></a>
</li>

  }else if ($user->role == 'superadmin'){
 <li class="nav-item">
    <a class="nav-link" href="page.php">
        <i class="fas fa-fw fa-tachometer-alt"></i>
        <span>Page4</span></a>
</li>

 }else if ($user->role == 'superadmin2'){
 <li class="nav-item">
    <a class="nav-link" href="page.php">
        <i class="fas fa-fw fa-tachometer-alt"></i>
        <span>Page5</span></a>
</li>

 }
?>

您可以使用嵌套if else或elseif也可以使用 next if in firstone's else like see below code

<?php

if ($user->role == 'admin'){
  // your query

   
 }else 

 if ($user->role == 'author'){
   // your query
 }else 
 if ($user->role == 'admin2'){
    // your query

 }else 
 if($user->role == 'admin1'){
    // your query
 }

 

 }
?>

標籤：php html css validation

上一篇：如何將預測結果中的集群ID轉換為R中k-means聚類預測模型中的類標簽？

下一篇：十進制數的Joi驗證無法正常作業