我有一個物件陣列 - 串列 []; 和一個物件 - obj;
這是串列陣列：
{
_id: new ObjectId("61840c5ce237f22a1c7a1ac7"),
name: 'list1',
content: [ 'aaaa' ],
description: 'aa',
tags: [],
lastmodified: 1,
__v: 0
},{
_id: new ObjectId("61840def80a88d1b2ffce400"),
name: 'list',
content: [ 'list!' ],
description: 'test',
tags: [],
__v: 0
}
這是 obj 物件：
{
_id: new ObjectId("61840def80a88d1b2ffce400"),
name: 'list',
content: [ 'list!' ],
description: 'test',
tags: [],
__v: 0
}
簡單問題：如何從“串列”中洗掉物件，類似于“obj”一個
uj5u.com熱心網友回復：
您可以使用 JavaScriptArray.filter()方法從串列中排除目標物件：
const list = [{
_id: new ObjectId("61840c5ce237f22a1c7a1ac7"),
name: 'list1',
content: [ 'aaaa' ],
description: 'aa',
tags: [],
lastmodified: 1,
__v: 0
},{
_id: new ObjectId("61840def80a88d1b2ffce400"),
name: 'list',
content: [ 'list!' ],
description: 'test',
tags: [],
__v: 0
}];
const targetObj = {
_id: new ObjectId("61840def80a88d1b2ffce400"),
name: 'list',
content: [ 'list!' ],
description: 'test',
tags: [],
__v: 0
};
const filteredList = list.filter((element) => element._id !== targetObj._id);
uj5u.com熱心網友回復：
使用某種過濾......這是一個想法。
items = [{
_id: new ObjectId("61840c5ce237f22a1c7a1ac7"),
name: 'list1',
content: [ 'aaaa' ],
description: 'aa',
tags: [],
lastmodified: 1,
__v: 0
},{
_id: new ObjectId("61840def80a88d1b2ffce400"),
name: 'list',
content: [ 'list!' ],
description: 'test',
tags: [],
__v: 0
}]
removeID = "61840def80a88d1b2ffce400"
items = [item for item in items if item['id'] != removeID]
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