我不知道如何將一個變數的每個資料值賦予另一個變數的值-有解無憂

const people = [{
    name: 'frank',
    age: 20,
    position: 'front-end-developer',
    value: 7
  },
  {
    name: 'craig',
    age: 27,
    position: 'back-end-developer',
    value: 7
  },
  {
    name: 'peter',
    age: 23,
    position: 'database-manager',
    value: 6
  },
  {
    name: 'andy',
    age: 29,
    position: 'full-stack-developer',
    value: 9
  }
];

const salaryGenerator = (person) => {
  return '$'   (person.value * 10 / 5 * 15   200)
};

const sentenceGenerator = (person) => {
  return person.name   ' is '   person.age   ' who works as a '   person.position
}

const userNameGenerator = (person, ) => {
  const randomWord = ['donec', 'pellentesque', 'facilisis', 'potenti']
  return person.name   (person.age * person.value   300)   randomWord[Math.floor(Math.random() * randomWord.length)]

}

const salary = people.map(salaryGenerator)
const sentence = people.map(sentenceGenerator)
const userName = people.map(userNameGenerator)
console.log(salary)
console.log(sentence);
console.log(userName);

我想在randomWord. 我希望它像frank440donec并username在最后給每個名字一個不同的無意義詞，但它給所有名字一個不同的無意義詞，除了兩個被分配相同的無意義詞。

uj5u.com熱心網友回復：

如果目標是從一組名稱中隨機分配——避免重復——那么一個好的解決方案是對名稱進行洗牌......

// names must be at least the length of the people array
const names = ['donec', 'pellentesque', 'facilisis', 'potenti'];
shuffle(names);

const userNameGenerator = (person, index) => {
  const randomWord = names[index];
  const ageXValue = person.age*person.value 300;
  return `${person.name}${ageXValue}${randomWord}`;
}

// shuffle based on  https://stackoverflow.com/a/12646864/294949
function shuffle(array) {
  for (let i = array.length - 1; i > 0; i--) {
    const j = Math.floor(Math.random() * (i   1));
    const temp = array[i];
    array[i] = array[j];
    array[j] = temp;
  }
}

const people = [{
    name: 'frank',
    age: 20,
    position: 'front-end-developer',
    value: 7
  },
  {
    name: 'craig',
    age: 27,
    position: 'back-end-developer',
    value: 7
  },
  {
    name: 'peter',
    age: 23,
    position: 'database-manager',
    value: 6
  },
  {
    name: 'andy',
    age: 29,
    position: 'full-stack-developer',
    value: 9
  }
];

console.log(people.map(userNameGenerator))

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標籤：javascript 数组

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