單擊某個復選框時我有幾個復選框checkbox,我想顯示一些內容(在我的情況下,這是一個簡單的示例塊)單擊另一個復選框時,前一個塊應該隱藏并顯示一個新塊,我想解決這個問題你需要應用forEach復選框為我作業,但我不能顯示塊
<div class="toggle-two">
<div><small>content 1</small></div>
<label class="switch-label">
<input class="switch" id="switch-novice" value="switch-novice" type="checkbox"/>
<span class="slider round"></span>
</label>
</div>
<div class="toggle-three">
<div><small>content 2</small></div>
<label class="switch-label">
<input class="switch" id="switch-intermediate" value="switch-intermediate" type="checkbox"/>
<span class="slider round"></span>
</label>
</div>
<div class="toggle-four">
<div><small>content 3</small></div>
<label class="switch-label">
<input class="switch" id="switch-expert" value="switch-expert" type="checkbox" />
<span class="slider round"></span>
</label>
</div>
<!-- ------------------------------------------- -->
</div>
<div>
<div class="content c1"></div>
<div class="content c2"></div>
<div class="content c3"></div>
</div>
**script.js**
let uploadPres = document.getElementsByClassName("content");
$(".content").each(function (index, value) {
$(`.switch:not([checked])`).on("change", function (param1, param2) {
$(".switch").not(this).prop("checked", false);
if ($(".switch").is(":checked")) {
console.log(this.checked);
}
});
});
最初一個名為 content 的類display: none在默認情況下具有
你也可以在codeandbox中看到這個例子
uj5u.com熱心網友回復:
在每個輸入復選框上添加相關內容 div 的參考,如下所示。
<input class="switch" id="switch-novice" value="switch-novice" type="checkbox" data-content="c1"/>
OR
<input class="switch" id="switch-novice" value="switch-novice" type="checkbox" data-content="c2"/>
現在只需更新您的代碼,如下所示。
$(`.switch`).on("change", function (a, b) {
$(".switch").not(this).prop("checked", false);
if ($(".switch").is(":checked")) {
var contentToOpen = $(this).data("content"); // read the associated class of the div
$(`.content`).hide(); // hide all existing opened ones
$(`.${contentToOpen}`).show(); // show the associated one
}
});
uj5u.com熱心網友回復:
function toggle(event){
var container = event.target.closest(".togglers");
var currentContainer = event.target.closest(".toggle");
var index = Array.from(container.children).indexOf(currentContainer);
var checkboxes = document.querySelectorAll(".toggle input");
$(checkboxes).prop("checked",false);
$(event.target).prop("checked", true);
var contentItems = document.querySelectorAll(".content-items .content");
$(contentItems).hide();
var content = contentItems[index];
$(content).slideToggle();
}
.content {
display: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="togglers">
<div class="toggle"><input type="checkbox" onclick="toggle(event)" />
toggle 1
</div>
<div class="toggle"><input type="checkbox" onclick="toggle(event)" />
toggle 2
</div>
<div class="toggle"><input type="checkbox" onclick="toggle(event)" />
toggle 3
</div>
</div>
<div class="content-items">
<div class="content">Content 1</div>
<div class="content">Content 2</div>
<div class="content">Content 3</div>
</div>
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標籤:javascript 查询 数组 复选框
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