SeleniumPython如何在兩個值之間找到//跨度數

HTML 示例：

<div class="lend-count">
<span>50</span>
</div>
<div class="lend-count">
<span>55</span>
</div>
<div class="lend-count">
<span>25</span>
</div>
<div class="lend-count">
<span>45</span>
</div>
<div class="lend-count">
<span>25</span>
</div>
<div class="lend-count">
<span>30</span>
</div>
<div class="lend-count">
<span>25</span>
</div>
<div class="lend-count">
<span>15</span>
</div>
<div class="lend-count">
<span>10</span>
</div>

在硒鉻網路驅動程式中。我試圖找到介于數字范圍 (10-20) 之間的第一個跨度，在本例中為15，然后單擊它。如果此頁面上沒有任何內容（拋出 NoSuchElementException），請單擊下一頁按鈕并回圈回傳重試：

        while True:
            try:
                driver.find_element(By.XPATH, "//span[number(.)= <10, >20]").click()
                time.sleep (1)
                break
            except NoSuchElementException:
                driver.find_element(By.XPATH, "//*[@class='anticon anticon-right']").click()                     
                time.sleep (1)

也嘗試使用范圍：

price = range (10,20) 
driver.find_element(By.XPATH, "//span[number(.)= 'price']").click()

請指教

uj5u.com熱心網友回復：

driver.find_element(By.XPATH,"//div[@class='lend-count']/span[number()>10 and number()<20]").click()

只需使用 number()>10 和 number()<20 即可獲取范圍之間的數字。要確保它出現，請使用 webdriver 等待。

wait=WebDriverWait(driver, 10)
wait.until(EC.element_to_be_clickable((By.XPATH,"//div[@class='lend-count']/span[number()>10 and number()<20]"))).click()

如果出現具有這些值的跨度，將檢查 10 秒，然后拋出例外。

while True:
    try:
        wait.until(EC.element_to_be_clickable((By.XPATH,"//div[@class='lend-count']/span[number()>10 and number()<20]"))).click()
        break
    except NoSuchElementException:
        wait.until(EC.element_to_be_clickable((By.XPATH,"//*[@class='anticon anticon-right']"))).click()            

進口

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait 
from selenium.webdriver.support import expected_conditions as EC

uj5u.com熱心網友回復：

您可以使用 XPath 將所有 Web 元素存盤//span[text()]在如下串列中，然后使用回圈進行迭代并放置條件if int(span_text.text) < 10 and int(span_text.text) >20。

代碼：

while True:
    try:
        list_of_span_tag_text = driver.find_elements(By.XPATH, "//span[text()]")
        for span_text in list_of_span_tag_text:
            if int(span_text.text) < 10 and int(span_text.text) >20:
                span_text.click()
                time.sleep(1)
                break
            else:
                print("None of the span on this page satisfy this condtion, span_text.text <10 and span_text.text > 20")
    except NoSuchElementException:
        driver.find_element(By.XPATH, "//*[@class='anticon anticon-right']").click()
        time.sleep(1)

更新 1：

while True:
    try:
        list_of_span_tag_text = driver.find_elements(By.XPATH, "//span[text() < 20][text() > 10]")
        for span_text in list_of_span_tag_text:
            span_text.click()
            time.sleep(1)
            break
        else:
            print("None of the span on this page satisfy this condtion, span_text.text < and span_text.text > 20")
    except NoSuchElementException:
        driver.find_element(By.XPATH, "//*[@class='anticon anticon-right']").click()
        time.sleep(1)

uj5u.com熱心網友回復：

您可以嘗試：while 1：

   len_click = 0 #remains 0 if no spans are in range 10-20
       try:
           #contains all the span with number in range.
           lst = driver.find_element(By.XPATH, "//span[number()>10][number()<20]") 
           len_click = len(lst)
           if(click!=0): #shows no span exist in range 10 to  20.
               lst[0].click
           else:
               #code for next page.
       except NoSuchElementException:
           #code for next page.    
     

如果您遇到任何問題，請在下面發表評論。

標籤：Python 硒 硒网络驱动程序 硒铬驱动器

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