Angular型別錯誤：未定義不是函式-有解無憂

selectedProjectInfo是選定專案的資料，其中ProjectAssignedUsers然后，我從 API獲得了getemployeesList，然后用欄位 a 修補資料并得到這個錯誤。

我想實作如果 Id,s 在兩個串列中匹配并且我得到了名字，那么這個名字在表單上

if(this.selectedProjectInfo.ProjectAssignedUsers)
this.selectedProjectInfo.ProjectAssignedUsers.forEach(
  this.getemployeesList.forEach((cacheEmployee: any) => {
    (backendAssignUser: any) => {
      if (
        cacheEmployee?.Id === backendAssignUser?.UserId &&
        backendAssignUser.UserAssignmentType === 1
      ) {
        this.salesRepList.push({
          FirstName: cacheEmployee?.FirstName,
          LastName: cacheEmployee?.LastName,
          UserTradeNames: cacheEmployee?.UserTradeNames,
          Id: cacheEmployee?.Id,
          UserAssignmentType: 1,

          Color: cacheEmployee?.Color,
        });
      } else if (
        cacheEmployee.Id === backendAssignUser.UserId &&
        backendAssignUser.UserAssignmentType === 2
      ) {
        this.estimatorsList.push({
          FirstName: cacheEmployee?.FirstName,
          LastName: cacheEmployee?.LastName,
          UserTradeNames: cacheEmployee?.UserTradeNames,
          Id: cacheEmployee?.Id,
          UserAssignmentType: 2,
          Color: cacheEmployee?.Color,
        });
      } else if (
        cacheEmployee.Id === backendAssignUser.UserId &&
        backendAssignUser.UserAssignmentType === 3
      ) {
        this.pmList.push({
          FirstName: cacheEmployee.FirstName,
          LastName: cacheEmployee.LastName,
          UserTradeNames: cacheEmployee.UserTradeNames,
          Id: cacheEmployee.Id,
          UserAssignmentType: 3,
          Color: cacheEmployee.Color,
        });
      }
    }
  }),

Angular 型別錯誤：未定義不是函式

uj5u.com熱心網友回復：

你搞砸了如何forEach在陣列上使用方法。

this.selectedProjectInfo.ProjectAssignedUsers.forEach(
  this.getemployeesList.forEach((cacheEmployee: any) => {

可能您想在第二個 forEach 中進行 1 次嵌套迭代。在這種情況下，正確的方法是以下

 this.selectedProjectInfo.ProjectAssignedUsers.forEach(
      (projectAssignedUser: any) => {
        this.getemployeesList.forEach((cacheEmployee: any) => {
              .....
              .....
      }

檢查以下簡單示例，并查看與您的代碼中產生的錯誤完全相同的錯誤

var array1 = [1, 2];
var array2 = [3, 4, 5];

array1.forEach(
    array2.forEach((array2Element) => {
             console.log(array2Element);
             }));

雖然以下是您想要和作業的嵌套回圈

var array1 = [1, 2];
var array2 = [3, 4, 5];

array1.forEach((array1Element)=> {
    array2.forEach((array2Element) => {
             console.log(array2Element);
             })
});

轉載請註明出處，本文鏈接：https://www.uj5u.com/shujuku/387158.html

標籤：有角的打字稿类型错误角12

上一篇：強制引數成為擴展（或部分）型別的其他屬性的鍵

下一篇：如何創建遞回型別？