我正在學習 REST API Django，希望您能耐心等待并幫助我理解以下案例。
在 myproject/abcapp/forms.py
from django import forms
from .models import *
class ProfileForm(forms.ModelForm):
class Meta:
model=Profile
fields = "__all__"
class Zoo_data_2020Form(forms.ModelForm):
class Meta:
model=Zoo_data_2020
fields = "__all__"
在 myproject/abcapp/models.py
from django.conf import settings
from django.db import models
class ProfileQuerySet(models.QuerySet):
pass
class ProfileManager(models.Manager):
def get_queryset(self):
return ProfileQuerySet(self.model,using=self._db)
class Profile(models.Model):
name=models.CharField(settings.AUTH_USER_MODEL,max_length=200)
subtype=models.CharField(max_length=500)
type=models.CharField(max_length=500)
gender=models.CharField(max_length=500)
objects = ProfileManager()
class Meta:
verbose_name = 'Profile'
verbose_name_plural = 'Profiles'
managed = False
db_table ='profiles'
def __str__(self):
return '{}'.format(self.name)
class Zoo_data_2020QuerySet(models.QuerySet):
pass
class Zoo_data_2020Manager(models.Manager):
def get_queryset(self):
return Zoo_data_2020QuerySet(self.model,using=self._db)
class Zoo_data_2020(models.Model):
name=models.CharField(max_length=200)
size=models.DecimalField(decimal_places=3,max_digits=100000000)
weight=models.DecimalField(decimal_places=3,max_digits=100000000)
age=models.DecimalField(decimal_places=3,max_digits=100000000)
objects = Zoo_data_2020Manager()
class Meta:
verbose_name = 'zoo_data_2020'
verbose_name_plural = 'zoo_data_2020s'
managed = False
db_table ='zoo_data_2020'
def __str__(self):
return '{}'.format(self.name)
在myproject/abcapp/api/views.py：
from rest_framework import generics, mixins, permissions
from rest_framework.views import APIView
from rest_framework.response import Response
import json
from django.shortcuts import get_object_or_404
from abcapp.models import *
from .serializers import *
def is_json(json_data):
try:
real_json = json.loads(json_data)
is_valid = True
except ValueError:
is_valid = False
return is_valid
class ProfileDetailAPIView(generics.RetrieveAPIView):
permission_classes = []
authentication_classes = []
queryset= Profile.objects.all()
serializer_class = ProfileSerializer
lookup_field = 'id'
class ProfileAPIView(generics.ListAPIView):
permission_classes = []
authentication_classes= []
serializer_class = ProfileSerializer
passed_id = None
search_fields = ('id','name','animal')
queryset = Profile.objects.all()
def get_queryset(self):
qs = Profile.objects.all()
query = self.request.GET.get('q')
if query is not None:
qs=qs.filter(name__icontains=query)
return qs
class Zoo_data_2020DetailAPIView(generics.RetrieveAPIView):
permission_classes = []
authentication_classes = []
queryset= Zoo_data_2020.objects.all()
serializer_class = Zoo_data_2020Serializer
lookup_field = ('id','name')
class Zoo_data_2020APIView(generics.ListAPIView):
permission_classes =[]
authentication_classes= []
serializer_class = Zoo_data_2020Serializer
passed_id = None
search_fields = ('id','name')
queryset = Zoo_data_2020.objects.all()
def get_queryset(self):
qs = Zoo_data_2020.objects.all()
query = self.request.GET.get('q')
if query is not None:
qs=qs.filter(name__icontains=query)
return qs
在myproject/abcapp/api/serializers.py：
from rest_framework import serializers
from abcapp.models import *
class ProfileSerializer(serializers.ModelSerializer):
class Meta:
model=Profile
fields = "__all__"
read_only_fields = ['name']
class Zoo_data_2020Serializer(serializers.ModelSerializer):
class Meta:
model = Zoo_data_2020
fields = "__all__"
read_only_fields = ['name']
在myproject/abcapp/api/urls.py：
from django.urls import path
from .views import *
urlpatterns = [
path('', ProfileAPIView.as_view()),
path('<id>/', ProfileDetailAPIView.as_view()),
path('', Zoo_data_2020APIView.as_view()),
path('<id>/', Zoo_data_2020DetailAPIView.as_view()),]
在myproject/urls.py：
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('api/profile/', include('abcapp.api.urls')),
path('api/zoodata2020/', include('abcapp.api.urls')),
]
因此，當我打電話時，我從表 Profilehttp://127.0.0.1:8000/api/profile/中獲取資料，但是當我打電話時，我再次從表 Profile 而不是 Zoo_data_2020 中獲取資料。但是當我從中洗掉時：http://127.0.0.1:8000/api/zoodata2020/myproject/abcapp/api/urls.py
path('', ProfileAPIView.as_view()),
path('<id>/', ProfileDetailAPIView.as_view()),
然后它向我顯示表格中的資料，Zoo_data_2020但我無法從表格 Profile 中獲取資料
如何解決？我確信我在應用程式和專案中的 urls.py 中都做錯了。那么我需要做什么才能使端點分開？以及如何展示它們？
我想呼叫http://127.0.0.1:8000/api/profile/?search=TIGER并因此向我提供來自表組態檔和 zoo_data_2020 的資訊，因為它們包含不同的資料但大約相同的“名稱”是 TIGER . 但是目前，例如，當我呼叫http://127.0.0.1:8000/api/profile/?search=TIGER時，它只顯示來自表格的資料而Profile不是來自Zoo_data_2020
請幫助理解它以及如何解決它。提前致謝。
uj5u.com熱心網友回復：
在專案 urls.py 中，您不必多次參考同一個應用程式，您可以在應用程式的 urls.py 中執行此操作
試試這個
我的專案/urls.py：
urlpatterns = [
path('admin/', admin.site.urls),
path('api/', include('cfs.api.urls')),
]
我的專案/abcapp/api/urls.py：
urlpatterns = [
path('profile', ProfileAPIView.as_view()),
path('profile/<id>/', ProfileDetailAPIView.as_view()),
path('zoo_data', Zoo_data_2020APIView.as_view()),
path('zoo_data/<id>/', Zoo_data_2020DetailAPIView.as_view()),
]
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