這是一個更通用的數學/代碼問題，在我的情況下，我需要它用于 Godot / GDScript。我有一個虛擬立方體定義為具有厚度偏移的原點，我回圈遍歷每個軸上的最小值和最大值以執行每個單元的動作。因此，普通立方體表示為：
const org = Vector3(32, 48, 64)
const thick = 16
const mins = Vector3(org.x - thick, org.y - thick, org.z - thick)
const maxs = Vector3(org.x thick, org.y thick, org.z thick)
for x in range(mins.x, maxs.x, thick):
for y in range(mins.y, maxs.y, thick):
for z in range(mins.z, maxs.z, thick):
var vec = Vector3(x, y, z)
發生的事情是我想將此立方體細分為 8 個彼此完美接觸的立方體。我需要一個mins_0/ maxs_0, mins_1/ maxs_1, ... , mins_7/maxs_7每個代表立方體的一部分。
我被困在數學上：我不知道如何轉置原點和厚度偏移，顯然保持順序，以便任何回圈都從正確的位置開始（mins.# < maxs.#總是）。我只知道兩種顯而易見的組合：
mins_0 = Vector3(org.x - thick, org.y - thick, org.z - thick)
maxs_0 = Vector3(org.x, org.y, org.z)
mins_4 = Vector3(org.x, org.y, org.z)
maxs_4 = Vector3(org.x thick, org.y thick, org.z thick)
如何以正確的順序填充其他 6 個空間以覆寫剩余區域？
uj5u.com熱心網友回復：
這使用矢量算術會簡單得多，但我們可以使用原始坐標來做到這一點：
mins_0 = Vector3(org.x - thick, org.y - thick, org.z - thick)
maxs_0 = Vector3(org.x, org.y, org.z)
mins_1 = Vector3(org.x - thick, org.y - thick, org.z)
maxs_1 = Vector3(org.x, org.y, org.z thick)
mins_2 = Vector3(org.x - thick, org.y, org.z - thick)
maxs_2 = Vector3(org.x, org.y thick, org.z)
mins_3 = Vector3(org.x - thick, org.y, org.z)
maxs_3 = Vector3(org.x, org.y thick, org.z thick)
mins_4 = Vector3(org.x, org.y - thick, org.z - thick)
maxs_4 = Vector3(org.x thick, org.y, org.z)
mins_5 = Vector3(org.x, org.y - thick, org.z)
maxs_5 = Vector3(org.x thick, org.y, org.z thick)
mins_6 = Vector3(org.x, org.y, org.z - thick)
maxs_6 = Vector3(org.x thick, org.y thick, org.z)
mins_7 = Vector3(org.x, org.y, org.z)
maxs_7 = Vector3(org.x thick, org.y thick, org.z thick)
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