PHP如何從for回圈中將整數相加

我有 2 個陣列。一個用于字母和所述字母的點。

我已經得到了用戶輸入的單詞并將其變成了一個陣列。

然后我回圈遍歷$letters陣列以找到單詞中每個字母的鍵。

接下來我回圈遍歷$points陣列以找到與字母位置對應的鍵值。我遇到的問題是，當我找到這些值時，我想將它們加在一起，但我做不到。 array_sum()給出一個錯誤，說它必須是一個陣列。

這是我的代碼：

<?php
$letters = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z", "ER", "CL", "IN", "TH", "QU"];

$points= [2, 8, 8, 5, 2, 6, 6, 7, 2, 13, 8, 3, 5, 5, 2, 6, 15, 5, 3, 3, 4, 11, 10, 12, 4, 14, 7, 10, 7, 9, 9];

if(isset($_POST['play'])) {
    //INDEX TO COUNT THROUGH 'letters' ARRAY
    $spot = "";
    $tally = 0;
    //GET WORD FROM USER AND UPPERCASE IT
    $ply1_word = strtoupper($_POST['player1']);
    //TURN WORD STRING INTO ARRAY
    $word_letters = str_split($ply1_word);
//    echo "<pre>";
//    print_r($word_letters);
//    echo "</pre>";
    for ($i = 0; $i < count($word_letters); $i  )  {
        if (in_array($word_letters[$i], $letters)) {
            $spot = array_search($word_letters[$i], $letters);
        }
        if (isset($values[$spot])) {
//            echo $values[$spot] . "<br>";
//            print_r($values[$spot]);
//            var_dump($values[$spot]);
//  NEED TO ADD NUMBERS TOGETHER HERE OR AFTER HERE
        }
    }
}

uj5u.com熱心網友回復：

您的代碼中有一些問題：

• 您正在使用的$valueswich 不存在，您應該將其替換為$points.
• 即使角色不在您的$letters（嘗試使用“測驗我”）中，您也會space添加積分，與T.
• 您的代碼無法處理您的最后一個字母 ( "ER", "CL", "IN", "TH", "QU")

您可以在不使用array_sum, 的情況下執行此操作 =：

$tally  = $points[$spot]

更進一步，您的代碼無法處理最后一個$letters，您也需要更改代碼以檢查這些字母。

作業代碼，有一些var_dump：

if(isset($_POST['play'])) {
    $spot = "";
    $tally = 0;
    //GET WORD FROM USER AND UPPERCASE IT
    $ply1_word = strtoupper($_POST['player1']);
    var_dump($ply1_word);
    //TURN WORD STRING INTO ARRAY
    $word_letters = str_split($ply1_word);
    print_r($word_letters);
    $skipNextLetter = false; // needed to handle "ER", "CL", "IN", "TH", "QU"
    for ($i = 0; $i < count($word_letters); $i  )  {
        // reset $spot to prevent adding points when char isn't in $letters
        $spot = '';
        // don't check this char if old one was a combination of two chars
        if ($skipNextLetter) {
            $skipNextLetter = false;
            continue;
        }
        $char = $word_letters[$i];
        $charTemp = $word_letters[$i];
        // handle "ER", "CL", "IN", "TH", "QU"
        if (isset($word_letters[$i   1])) {
            $charTemp .= $word_letters[$i   1];
            var_dump('===> check with next char :: ' . $charTemp);
            if (in_array($charTemp, ['ER', 'CL', 'IN', 'TH', 'QU'])) {
                $char = $charTemp;
                $skipNextLetter = true;
            }
        }
        if (in_array($char, $letters)) {
            $spot = array_search($char, $letters);
        }
        var_dump('CHAR => ' . $char . ' / SPOT => ' . $spot);
        if (isset($points[$spot])) {
           echo $points[$spot] . "<br>";
        //    print_r($points[$spot]);
           var_dump('ADDING POINTS : ' . $points[$spot]);
//  NEED TO ADD NUMBERS TOGETHER HERE OR AFTER HERE
            $tally  = $points[$spot];
        }
    }

結果 ：

$test = 'Stackoverflow';
// $tally = 65

$test = 'Stackoverflow Clean';
// $tally = 84

正如弗里茨所說，我會以不同的方式做事（即用array_values）

uj5u.com熱心網友回復：

您的代碼（原樣）幾乎可以正常作業。

您只需要添加幾個修復程式。

上面寫著：

 if (isset($values[$spot])) {

您沒有在任何地方宣告 $values 變數，所以我假設您的意思是：

 if (isset($points[$spot])) {

最后，要總計實際點值，您可以使用以下內容（在修復上述行之后）：

if (isset($points[$spot])) {
    $tally  = $points[$spot];
}

總而言之：

<?php
$letters = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z", "ER", "CL", "IN", "TH", "QU"];

$points= [2, 8, 8, 5, 2, 6, 6, 7, 2, 13, 8, 3, 5, 5, 2, 6, 15, 5, 3, 3, 4, 11, 10, 12, 4, 14, 7, 10, 7, 9, 9];

if(isset($_POST['play'])) {
    //INDEX TO COUNT THROUGH 'letters' ARRAY
    $spot = "";
    $tally = 0;
    //GET WORD FROM USER AND UPPERCASE IT
    $ply1_word = strtoupper($_POST['player1']);
    //TURN WORD STRING INTO ARRAY
    $word_letters = str_split($ply1_word);
//    echo "<pre>";
//    print_r($word_letters);
//    echo "</pre>";
    for ($i = 0; $i < count($word_letters); $i  )  {
        if (in_array($word_letters[$i], $letters)) {
            $spot = array_search($word_letters[$i], $letters);
        }
        if (isset($points[$spot])) {
//            echo $values[$spot] . "<br>";
//            print_r($values[$spot]);
//            var_dump($values[$spot]);
//  NEED TO ADD NUMBERS TOGETHER HERE OR AFTER HERE
              $tally  = $points[$spot];
        }
    }
    // Maybe print the Word and tally here?
    echo $ply1_word . " has score of " . $tally . "<br>";


}

話雖如此，我會做完全不同的事情。

對于初學者，我會使用一個關聯陣列，其中字符是鍵，點是值。

不過，只要您修復了上述錯誤，您的解決方案就可以使用。

問候，弗里茨。

uj5u.com熱心網友回復：

@micster 提出的觀點非常正確。只是為了讓您了解如何以完全不同的方式解決此問題（使用array_reduce）：

<?php

$scores = [
    "A" => 2, "B" => 8, "C" => 8, "D" => 5, "E" => 2, 
    "F" => 6, "G" => 6, "H" => 7, "I" => 2, "J" => 13, 
    "K" => 8, "L" => 3, "M" => 5, "N" => 5, "O" => 2, 
    "P" => 6, "Q" => 15, "R" => 5, "S" => 3, "T" => 3, 
    "U" => 4, "V" => 11, "W" => 10, "X" => 12, "Y" => 4, 
    "Z" => 14, "ER" => 7, "CL" => 10, "IN" => 7, "TH" => 9, 
    "QU" => 9,
];

$word = 'thesaurus';

$wordScore = array_reduce(str_split($word, 2), function($carriedScore, $charPair) use ($scores) {
    $charPair = strtoupper($charPair);

    if(isset($scores[$charPair])) {
        $score = $scores[$charPair];
    } else {
        $score = $scores[$charPair[0]] ?? 0;
        $score  = $scores[$charPair[1]] ?? 0;
    }

    return $carriedScore   $score;
}, 0);

var_dump($wordScore); // 32

這段代碼背后的總體思路是，我們首先將輸入的單詞拆分為兩個字符的組合。因此，按照示例，我們正在創建一個陣列：[ th, es, au, ru, s ]. 然后，對于每個專案，我們正在檢查該組合是否存在于我們的$scores陣列中。如果沒有，我們只是將各個字符的分陣列合起來。

這段代碼還存在一個缺陷。如果您的單詞是第十個（[ te, nt, h ]），它將被評分為t e n t h和不是t e n th。

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