*對不起，如果標題沒有意義，我不知道如何措辭
所以我開始在 Pycord 的庫中制作一個 python discord bot。我想制作一個可以在多臺服務器上作業的機器人，每臺服務器都有不同的值。因此，為此，我制作了一個字典，將所有這些值存盤在一個嵌套字典中。但是，當我嘗試更改一個嵌套字典的值時，它會更改其他嵌套字典中的值。
代碼：
testing_servers = [912361242985918464, 938245167880753202]
server_ids = {}
default_server_vals = {'beetle_game_started': False, 'beetle_message_id': None,
'beetle_message_channel': None, 'beetle_player_1': None, 'beetle_player_2': None, 'beetle_game_on': False, 'player1_list' : [], "player2_list":[]}
@bot.event
async def on_ready():
print('logged in')
for i in bot.guilds:
global server_ids
global default_server_vals
server_ids[str(i.id)] = default_server_vals
print(server_ids)
@bot.event
async def on_guild_join(guild):
server_ids[str(guild.id)] = default_server_vals
@bot.slash_command(guild_ids=testing_servers, name="test", description="Test out bot latency")
async def test(ctx):
await ctx.respond(f"Bot Latency: {bot.latency * 100}")
@bot.slash_command(guild_ids=testing_servers, name="eightball", description="Play 8ball with friends")
async def eightball(ctx, question):
eightball_int = random.randint(1, 5)
response = None
if eightball_int == 1:
response = "I don't quite know"
if eightball_int == 2:
response = "Well no."
if eightball_int == 3:
response = "Yes of course!"
if eightball_int == 4:
response = "Maybe it's best not to answer."
if eightball_int == 5:
response = "Bruh Moment."
embed = discord.Embed(title="Eightball", description=f"""You asked: {question}
My response: {response}""", colour=discord.Colour.green())
await ctx.respond(embed=embed)
@bot.slash_command(guild_ids=testing_servers, name="roll_dice", description="Roll a dice!")
async def roll_dice(ctx, sides: int):
dice_int = random.randint(1, int(sides))
embed = discord.Embed(title="Dice", colour=discord.Colour.green())
embed.add_field(name="You rolled a:", value=str(dice_int))
embed.add_field(name="Dice sides:", value=str(sides))
await ctx.respond(embed=embed)
@bot.slash_command(guild_ids=testing_servers, name="beetle", description="2 Player game")
async def beetle(ctx):
print(server_ids[str(ctx.guild.id)].get('beetle_game_on'), server_ids[str(ctx.guild.id)].get('beetle_game_started'))
if server_ids[str(ctx.guild.id)].get('beetle_game_on') == False and server_ids[str(ctx.guild.id)].get('beetle_game_started') == False:
await ctx.respond("Game starting! React to join.")
game_start_embed = discord.Embed(title="React to join beetle game! (2 Players Only)",
colour=discord.Colour.green())
game_start_embed.add_field(name="GAME RULES", value="""There are two players. There is one dice! The first player to finish the beetle drawing wins.
Rolling a 1 – Body
Rolling a 2 – Head
Rolling a 3 – A leg
Rolling a 4 – An eye
Rolling a 5 – An antenna
Rolling a 6 – The tail
The first player to roll all 6 wins. However, the head and body must be drawn first to draw the other beetle parts.""")
message = await ctx.send(embed=game_start_embed)
await message.add_reaction("??")
print(ctx.guild.id)
server_ids[str(ctx.guild.id)]['beetle_game_started'] = True
print(server_ids)
server_ids[str(ctx.guild.id)]['beetle_message_id'] = message.id
server_ids[str(ctx.guild.id)]['beetle_message_channel'] = message.channel
elif server_ids[str(ctx.guild.id)].get('beetle_game_started'):
await ctx.respond("Someone already started a game! Try and join them.")
else:
await ctx.respond("There is already a beetle game playing!")
這在 on_ready 中所做的是獲取機器人已經在其中的服務器 IDS，并將其放入全域 server_ids 變數中。然后嵌套字典作為字典的服務器 ID 值給出。但是，當我嘗試編輯嵌套字典的值（在甲蟲斜線命令內）時，它會更改所有其他嵌套值。
例如，當我嘗試更改 beetle_game_started 的嵌套字典值時，它會列印：
{'912361242985918464': {'beetle_game_started': True, 'beetle_message_id': None, 'beetle_message_channel': None, 'beetle_player_1': None, 'beetle_player_2': None, 'beetle_game_on': False, 'player1_list': [], 'player2_list': []}, '938245167880753202': {'beetle_game_started': True, 'beetle_message_id': None, 'beetle_message_channel': None, 'beetle_player_1': None, 'beetle_player_2': None, 'beetle_game_on': False, 'player1_list': [], 'player2_list': []}}
它以某種方式更改了服務器 IDS 的兩個嵌套字典的值（'beetle_game_started' 的值） 我如何更改一個嵌套字典的值而不更改其他字典的值？謝謝。
uj5u.com熱心網友回復：
您看到這種行為的原因是因為在 python 字典中是可變物件。
從提供的代碼中提取相關部分
default_server_vals = {'beetle_game_started': False, 'beetle_message_id': None,
'beetle_message_channel': None, 'beetle_player_1': None, 'beetle_player_2': None, 'beetle_game_on': False, 'player1_list' : [], "player2_list":[]}
和
server_ids[str(i.id)] = default_server_vals
server_ids[str(i.id)] 分配只是創建對單個字典的新參考。這就是為什么當您更改一個 id 的值時，您會觀察到所有其他 id 的更改。
解決此問題的一種方法是制作副本。我建議看看 python 的復制庫https://docs.python.org/3/library/copy.html
由于 default_server_vals 包含串列作為值，因此您需要考慮 deepcopy
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