如何在NodeJS中合并具有相同屬性的兩個物件

我有一個這樣的 JSON 資料：

"Data": [
            {
                "time": "18:40:43",
                "count": 7,
                "endTime": "15:46:25",
                "date": "2019-01-16",
                "dow": "Thursday"
            },
            {
                "count": 11,
                "time": "16:39:52",
                "endTime": "19:41:03",
                "dow": "Thursday",
                "date": "2019-01-16"
            },
]

我想合并這個陣列中的兩個物件，但它具有相同的屬性，例如date，dow

最后我想表示這樣的資料：

"Data": [
            {
                "time": "16:39:52",
                "count": 18,
                "date": "2019-01-16",
                "dow": "Thursday"
                "endTime": "19:41:03",
            },
]

time: 應該是兩個物件中最小的，endTime應該是兩個物件中最大的 count應該是兩者的總和。date并且dow在兩個物件中都很常見

如何在節點 JS 中以這種方式合并這些物件？

uj5u.com熱心網友回復：

const data=[
            {
                "time": "18:40:43",
                "count": 7,
                "endTime": "15:46:25",
                "date": "2019-01-16",
                "dow": "Thursday"
            },
            {
                "count": 11,
                "time": "16:39:52",
                "endTime": "19:41:03",
                "dow": "Thursday",
                "date": "2019-01-16"
            },
];
let date=(time)=>new Date().setHours(...time.split(":"));

let newData=[];
data.forEach((item)=>{
  let findItem=newData.findIndex((e)=>e.date===item.date && e.dow===item.dow);
  if(findItem!=-1){
  let find=data.filter((e)=>e.dow===item.dow && e.date===item.date);
  let time=find.filter((i)=>find.find(i2=>date(i2.time)>date(i.time)));
    let endTime=find.filter((i)=>find.find(i2=>date(i2.endTime)<date(i.endTime)));
  item.endTime=endTime?.[0]?.endTime || item?.endTime;
  item.time=time?.[0]?.time || item?.time;
  item.count=find.map((e)=>e.count).reduce((partialSum, a) => partialSum   a, 0);
   let findItem=newData.findIndex((e)=>e.date===item.date && e.dow===item.dow);
   if(findItem!=-1) newData.splice(findItem,1);
   newData.push(item);
  }

 else newData.push(item);
});
console.log(newData);

uj5u.com熱心網友回復：

這是一個簡單易讀的答案：

const data = [
  {
    time: "18:40:43",
    count: 7,
    endTime: "15:46:25",
    date: "2019-01-16",
    dow: "Thursday",
  },
  {
    count: 11,
    time: "16:39:52",
    endTime: "19:41:03",
    dow: "Thursday",
    date: "2019-01-16",
  },
];
const mergeObjects = (data) => {
  mergedObj = { ...data[0] };
  for (i = 1; i < data.length; i  ) {
    const obj = data[i];
    for (const key in obj) {
      switch (key) {
        case "count":
          mergedObj.count = (mergedObj.count || 0)   obj.count;
        case "time":
          mergedObj.time =
            mergedObj.time < obj.time ? mergeObjects.time : obj.time;
        case "endTime":
          mergedObj.endTime = mergedObj.endTime > obj.endTime ? mergeObjects.endTime : obj.endTime;
      }
    }
  }
  return mergedObj;
};

console.log(mergeObjects(data));

輸出

{
    "time": "16:39:52",
    "count": 18,
    "date": "2019-01-16",
    "dow": "Thursday"
    "endTime": "19:41:03",
},

uj5u.com熱心網友回復：

假設

• “資料”里面只有兩個物件
• 時間將采用“HH::MM::SS”格式

將值傳遞給constructJSON實用函式，該函式將回傳格式化的值

var Data = [
            {
                "time": "18:40:43",
                "count": 7,
                "endTime": "15:46:25",
                "date": "2019-01-16",
                "dow": "Thursday"
            },
            {
                "count": 11,
                "time": "16:39:52",
                "endTime": "19:41:03",
                "dow": "Thursday",
                "date": "2019-01-16"
            },
]


function constructJSON(data)
{
 const returnData = {}
 returnData['count'] = data[0].count   data[1].count
 returnData['date'] = data[0].date    // since its common for both
 returnData['dow'] = data[0].dow      // since its common for both
 returnData['time'] = parseInt(data[0].time.split(':').join(''),10) < parseInt(data[1].time.split(':').join(''),10) ? data[0].time:data[1].time;
  returnData['endTime'] = parseInt(data[0].endTime.split(':').join(''),10) > parseInt(data[1].endTime.split(':').join(''),10) ? data[0].endTime:data[1].endTime;
 
  return returnData
}

console.log(constructJSON(Data))

uj5u.com熱心網友回復：

另一種合并方式

const data = [{"time": "18:40:43","count": 7,"endTime": "15:46:25","date": "2019-01-16","dow": "Thursday"},{"count": 11,"time": "16:39:52","endTime": "19:41:03","dow": "Thursday","date": "2019-01-16"}];

const [first, last] = data;

const result = {
    ...first,
    ...last,
    count: first.count   last.count,
    time: (new Date(`2000-01-01 ${first.time}`) < new Date(`2000-01-01 ${last.time}`)) ? first.time : last.time,
    endTime: (new Date(`2000-01-01 ${first.endTime}`) > new Date(`2000-01-01 ${last.endTime}`)) ? first.endTime : last.endTime
};

console.log(result);

.as-console-wrapper{min-height: 100%!important; top: 0}

標籤：javascript 节点.js 数组 json 目的

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