如何查找重疊預訂

我正在創建一個預訂系統，我希望我的函式is_reserved回傳一個已安排的新預訂或一條訊息說“已經有預訂”

from datetime import datetime

def is_reserved(request):
    start_request = to_date(request['start'])
    stop_request = to_date(request['end'])
    flag = False
    for reservation in range(len(reservations)):
        start = to_date(reservations[reservation]['start'])
        stop = to_date(reservations[reservation]['end'])
        if start_request > start and stop_request < stop:
            print("There's already a reservation!")
            flag = True
            break
    if flag == False:
        reservations.append(request)
        print("There wasn't a reservation, new reservation made")
        

def to_date(request):
    return datetime.strptime(request, '%Y-%m-%dT%H:%M:%S' "Z")

def see(list):
    for reservation in range(len(reservations)):
        print(reservations[reservation])

reservations = []


res1 = {
    'id' :1,
    'start':datetime(2022,2,23,hour=14, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z",
    'end':datetime(2022,2,23,hour=15, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z"
}

reservations.append(res1)

res2 = {
    'id' :2,
    'start':datetime(2022,2,23,hour=16, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z",
    'end':datetime(2022,2,23,hour=18, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z"
}

res3 = {
    'id' : 3,
    'start' : datetime(2022,2,23,hour=18, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z",
    'end': datetime(2022,2,23,hour=19, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z"
}

res4 = {
    'id' : 4,
    'start' : datetime(2022,2,23,hour=15, minute=30).strftime('%Y-%m-%dT%H:%M:%S')   "Z",
    'end': datetime(2022,2,23,hour=17, minute=50).strftime('%Y-%m-%dT%H:%M:%S')   "Z"
}

see(reservations)

is_reserved(res2)

see(reservations)

is_reserved(res3)

see(reservations)

is_reserved(res4)

see(reservations)

我得到這些結果：

{'id': 1, 'start': '2022-02-23T14:00:00Z', 'end': '2022-02-23T15:00:00Z'}
There wasn't a reservation, new reservation made
{'id': 1, 'start': '2022-02-23T14:00:00Z', 'end': '2022-02-23T15:00:00Z'}
{'id': 2, 'start': '2022-02-23T16:00:00Z', 'end': '2022-02-23T18:00:00Z'}
There wasn't a reservation, new reservation made
{'id': 1, 'start': '2022-02-23T14:00:00Z', 'end': '2022-02-23T15:00:00Z'}
{'id': 2, 'start': '2022-02-23T16:00:00Z', 'end': '2022-02-23T18:00:00Z'}
{'id': 3, 'start': '2022-02-23T18:00:00Z', 'end': '2022-02-23T19:00:00Z'}
There wasn't a reservation, new reservation made
{'id': 1, 'start': '2022-02-23T14:00:00Z', 'end': '2022-02-23T15:00:00Z'}
{'id': 2, 'start': '2022-02-23T16:00:00Z', 'end': '2022-02-23T18:00:00Z'}
{'id': 3, 'start': '2022-02-23T18:00:00Z', 'end': '2022-02-23T19:00:00Z'}
{'id': 4, 'start': '2022-02-23T15:30:00Z', 'end': '2022-02-23T17:50:00Z'}

問題是第四次預訂通常無法完成，因為已經有第二次預訂了。在我的 for 回圈中，我將預訂請求與已經進行的所有其他預訂進行比較，但是一對一比較并不能讓函式查看之后或之前是否有預訂，這就是我要阻止的地方。

如果您對我如何解決這個問題有任何想法，請。

uj5u.com熱心網友回復：

例如，實作這一目標的最佳方法是使用多個“房間”。在這種情況下，房間用常數 CONN 表示，在您的情況下它等于 1。

 from datetime import datetime

arrivals = []
departures = []
CONN = 1

def to_date(request):
    return datetime.strptime(request, '%Y-%m-%dT%H:%M:%S' "Z")

def reserve(request):
    start_request = to_date(request['start'])
    stop_request = to_date(request['end'])

    arrivals.append(start_request)
    departures.append(stop_request)


    arrivals.sort()
    departures.sort()
    
    for i in range(len(arrivals)):
        if i CONN < len(arrivals) and arrivals[CONN i] < departures[i]:
            arrivals.pop(len(arrivals)-1)
            departures.pop(len(arrivals)-1)
            print("We can't make the reservation")
            return False
    print("Reservation made!")
    reservations.append(request)
    see(reservations)
    return True

def see(list):
    print("Reservations: ")
    for reservation in range(len(reservations)):
        print(reservations[reservation])

reservations = []


res1 = {
    'id' :1,
    'start':datetime(2022,2,23,hour=14, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z",
    'end':datetime(2022,2,23,hour=15, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z"
}



res2 = {
    'id' :2,
    'start':datetime(2022,2,23,hour=16, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z",
    'end':datetime(2022,2,23,hour=18, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z"
}

res3 = {
    'id' : 3,
    'start' : datetime(2022,2,23,hour=18, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z",
    'end': datetime(2022,2,23,hour=19, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z"
}

res4 = {
    'id' : 4,
    'start' : datetime(2022,2,23,hour=18, minute=30).strftime('%Y-%m-%dT%H:%M:%S')   "Z",
    'end': datetime(2022,2,23,hour=19, minute=0).strftime('%Y-%m-%dT%H:%M:%S')   "Z"
}

reserve(res1)
reserve(res2)
reserve(res3)
reserve(res4)
see(reservations)

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