import tweepy
import os
from PIL import Image
consumer_key = "hidden"
consumer_secret = "hidden"
access_token = "hidden"
access_token_secret = "hidden"
auth = tweepy.OAuth1UserHandler(
consumer_key, consumer_secret, access_token, access_token_secret
)
api = tweepy.API(auth, parser=tweepy.parsers.JSONParser())
# Upload images and get media_ids
filename = "test01.jpg"
media = api.media_upload(filename)
# Tweet with multiple images
api.update_status(status='Test 1 image', media_ids=[media.media_id_string])
我得到的錯誤是 -
Traceback (most recent call last):
File "/Users/anildhage/Coding-Workspace/twitter-bot/imdb bot/twitter_test.py", line 26, in <module>
api.update_status(status='Test 1 image', media_ids=[media.media_id_string])
AttributeError: 'dict' object has no attribute 'media_id_string'
ERROR conda.cli.main_run:execute(33): Subprocess for 'conda run ['python', '/Users/anildhage/Coding-Workspace/twitter-bot/imdb bot/twitter_test.py']' command failed. (See above for error)
我看了很多文章和 youtube 視頻，上面的代碼有效但不適合我。我在這里做錯了什么？
uj5u.com熱心網友回復：
由于您使用的是 JSON 決議器，media因此成為一個 dict 物件，因此您應該像這樣訪問它：
api.update_status(status='Test 1 image', media_ids=[media['media_id_string'])
如果您希望將其用作屬性，只需parser=...從您的tweepy.API通話中洗掉：
api = tweepy.API(auth)
轉載請註明出處，本文鏈接：https://www.uj5u.com/shujuku/451304.html