我有這個 div，我想問是否可以僅使用 1 個 XPATH 命令選擇帶有 XPATH 的“TEXT_I_NEED_X”？
我能選擇的最接近的就是這個，但它選擇的比我需要的多：
//div[@]/p//text()
<div class="article-text-with-img">
<p>
<a href="#"> Text1 </a>
</p>
<p> </p>
<p>
TEXT_I_NEED_A
<a href="#"> Text2 </a>
</p>
<p>
<span>
TEXT_I_NEED_B
<a href="#"> Text3 </a>
</span>
</p>
<p>
<span>
<span>
TEXT_I_NEED_C
<a href="#"> Text4 </a>
</span>
</span>
</p>
<p>
<span>
TEXT_I_NEED_D
</span>
<a href="#"> Text5 </a>
</p>
<p>
<span>
<spam>
TEXT_I_NEED_D
</span>
<a href="#"> Text5 </a>
</span>
</p>
</div>uj5u.com熱心網友回復：
使用單個 XPath 運算式：
//div[@]//a/parent::*/text() | //div[@]//a/preceding-sibling::span/text()
在命令列上xmllint（新行和空格包含在 text() 中）
xmllint --html --xpath '//div[@class="article-text-with-img"]//a/parent::*/text() | //div[@class="article-text-with-img"]//a/preceding-sibling::span/text()' test.html
TEXT_I_NEED_A
TEXT_I_NEED_B
TEXT_I_NEED_C
TEXT_I_NEED_D
TEXT_I_NEED_E
uj5u.com熱心網友回復：
示例beautifulsoup：
from bs4 import BeautifulSoup
html_doc = <YOUR HTML SNIPPET FROM THE QUESTION>
soup = BeautifulSoup(html_doc, "html.parser")
article = soup.select_one(".article-text-with-img")
for a in article.select("a"):
a.extract()
text = [t for a in article.find_all(text=True) if (t := a.strip())]
print(text)
印刷：
['TEXT_I_NEED_A', 'TEXT_I_NEED_B', 'TEXT_I_NEED_C', 'TEXT_I_NEED_D', 'TEXT_I_NEED_D']
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