top_imdb_movies = ['The Shawshank Redemption', 'The Godfather', 'The Dark Knight']
我將如何迭代 top_imdb_movies 以顯示以下有序串列：
1.The Shawshank Redemption
2.The Godfather
3.The Dark Knight
uj5u.com熱心網友回復：
也許像
i=1
for movie in top_imdb_movies:
print(f"{i}. {movie}"
i = i 1
uj5u.com熱心網友回復：
top_imdb_movies = ['1. The Shawshank Redemption', '2. The Godfather', '3. The Dark Knight']
for i in top_imbd_movies:
print(i)
uj5u.com熱心網友回復：
使用起始值為 1 的列舉，如下所示：
top_imdb_movies = ['The Shawshank Redemption', 'The Godfather', 'The Dark Knight']
for i, movie in enumerate(top_imdb_movies, 1):
print(f'{i}. {movie}')
輸出：
1. The Shawshank Redemption
2. The Godfather
3. The Dark Knight
uj5u.com熱心網友回復：
top_imdb_movies = ['The Shawshank Redemption', 'The Godfather', 'The Dark Knight']
movie_number=0
for movie_number, movie in enumerate(top_imdb_movies):
print(f"{movie_number 1}. {movie}")
輸出
1. The Shawshank Redemption
2. The Godfather
3. The Dark Knight
uj5u.com熱心網友回復：
通過組合函式：
top_imdb_movies = ['The Shawshank Redemption', 'The Godfather', 'The Dark Knight']
print(*map('{}.{}'.format, range(1, 1 len(top_imdb_movies)), top_imdb_movies), sep='\n')
添加sep='\n'引數print并擴展可迭代物件*以避免for-loop
如果串列很長，您可以將模板字串定義為變數以獲得更好的性能，template = '{}.{}'
template = '{}.{}'
print(*map(template.format, range(1, 1 len(top_imdb_movies)), top_imdb_movies), sep='\n')
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