如下表資料
lableA lableB lableC
1 1 1
1 2 1
2 1 1
2 3 1
3 1 1
3 4 1
我要得到的結果,以lableC為維度,統計lableB中不包含3的lableA去重的個數,結果如下:
lableC count
1 2
uj5u.com熱心網友回復:
select lableC,count(distinct labelA) as [count]
from tb a
where not exists(select 1 from tb b where labelB=3 and a.labelA =b.labelA)
group by labelC
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標籤:MySQL
