我需要幫助!我需要知道如何檢測 upload.php 檔案的按鈕名稱,以便我可以輸入 if(isset($_post['aa'))
<script type="text/javascript">
$(document).ready(function (e) {
$("#uploadForm").on('submit',(function(e) {
e.preventDefault();
var form = $(this);
var url = form.attr('action');
$.ajax({
url: "upload.php",
type: "POST",
data: new FormData(this),
contentType: false,
cache: false,
processData:false,
success: function(data)
{
$("#targetLayer").html(data);
},
error: function()
{
}
});
}));
});
</script>
表格
<form id="uploadForm" action="upload.php" method="post">
<div class="row">
<div class="col-md-12 mb-1">
<div id="targetLayer">No Image</div>
</div>
<div class="col-md-12">
<div class="form-group">
<input name="text" type="text" class="inputFile form-control" />
</div>
</div>
<div class="col-md-12">
<div class="form-group">
<input name="userImage" type="file" class="inputFile form-control" />
</div>
</div>
<div class="col-md-12">
<div class="form-group text-center">
<input type="submit" value="Save" name="aa" class="btnSubmit btn btn-success" />
</div>
</div>
</div>
</form>
uj5u.com熱心網友回復:
<form id="uploadForm" action="upload.php" method="post">
<div class="row">
<div class="col-md-12 mb-1">
<div id="targetLayer">No Image</div>
</div>
<div class="col-md-12">
<div class="form-group">
<input name="text" type="text" class="inputFile form-control" />
</div>
</div>
<div class="col-md-12">
<div class="form-group">
<input name="userImage" type="file" class="inputFile form-control" />
</div>
</div>
<div class="col-md-12">
<div class="form-group text-center">
<input type="submit" value="Save" name="aa" class="btnSubmit btn btn-success" />
</div>
</div>
</div>
</form>
這是我的表格
uj5u.com熱心網友回復:
在這種形式中,您提到按鈕的名稱是aa
這樣,它將變成
if(isset($_POST['aa']) && $_POST['aa'] == 'Save') ...
uj5u.com熱心網友回復:
提交按鈕通常不會/自動在 ajax 請求中發送。
它們不會添加到FormData或.serialize()。
在您的代碼中,手動添加此欄位。
<script type="text/javascript">
$(document).ready(function (e) {
$("#uploadForm").on('submit',(function(e) {
e.preventDefault();
var form = $(this);
var url = form.attr('action');
var formData = new FormData(this);
formData.append('aa', 'Save');
$.ajax({
url: "upload.php",
type: "POST",
data: formData,
contentType: false,
cache: false,
processData:false,
success: function(data)
{
$("#targetLayer").html(data);
},
error: function()
{
}
});
}));
});
</script>
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