爪哇。我想重復字串中的單詞，但是我的代碼出了點問題

我只想重復輸入字串中的單詞。但是輸出的順序不對。這是我的代碼：

  public static String repeatWords(String s, int num){
    StringBuilder sb = new StringBuilder();
    StringBuilder sbtemporary = new StringBuilder();
    int leng = s.length();
    for (int i=0; i < leng; i  ){
      char c = s.charAt(i);
      int b = (int) c;
      if (b >= 65 && b <= 90 || b >= 97 && b <= 122){
        sbtemporary.append(c);
      } else if (b == 32){
        sbtemporary.append(" ");
      }
      if (b == 32){
        for (int j = 1; j<= num-1; j  ){
          sb = sb.append(" "   sbtemporary);
          sbtemporary.delete(0,sbtemporary.length());
        }
      }
      sb.append(c);
    }
    String str = sb.toString();
    return str;
  }

s 是輸入字串，num 是需要重復的次數。我想要的結果是：

  When the input is : "How are you? I am fine."  
  The output should be like: "How How are are you you?"

但我的代碼的結果是：

"How How  are are  you? you  I I  am am  fine."

我真的不知道哪里出了問題，有人可以幫助我嗎？

uj5u.com熱心網友回復：

    System.out.println((int) "?".charAt(0)); //63
    System.out.println((int) ".".charAt(0)); //46

“？” 和 ”。” 不要附加到 sbtemporary。

uj5u.com熱心網友回復：

更正的代碼：-

public static String repeatWords(String s, int num){
    StringBuilder sb = new StringBuilder();
    StringBuilder sbtemporary = new StringBuilder();
    int leng = s.length();
    for (int i=0; i < leng; i  ){
      char c = s.charAt(i);
      int b = (int) c;
      if (b >= 65 && b <= 90 || b >= 97 && b <= 122){
        sbtemporary.append(c);
      }
      if (b == 32 && sbtemporary.length() != 0){
        for (int j = 1; j<= num-1; j  ){
          sb.append(" "   sbtemporary);
        }
        sbtemporary.delete(0,sbtemporary.length());
      }
      sb.append(c);
    }
    String str = sb.toString();
    return str;
  }

變化：-

1. 洗掉了將空間附加到 sbtemporary 的 else if (b == 32) 部分。
2. 洗掉 j 回圈之外的 sbtemporary 內容，否則它僅適用于 num == 2。
3. 在 if 條件 b == 32 中，如果 sbtemporary 不為空，則再添加一個條件。

uj5u.com熱心網友回復：

添加此檢查，并將重復部分添加到 sbtemporary。 System.out.println(repeatWords(str, 1));

if ( b == 63) {
    sb = sb.append(" "   sbtemporary);
    sb.append(c);
    break;  
}

if (b == 63) {                  
   for (int j = 1; j<= num; j  ){
      sb.append(" "   sbtemporary);
   }

   sb.append(c);
    break;
}
 
public static String repeatWords(String s, int num) {
        StringBuilder sb = new StringBuilder();
        StringBuilder sbtemporary = new StringBuilder();
        int leng = s.length();

        for (int i = 0; i < leng; i  ) {
            char c = s.charAt(i);
            int b = (int) c;

            if (b == 63) {                  
                for (int j = 1; j<= num; j  ){
                   sb.append(" "   sbtemporary);
                }
                
                sb.append(c);
                break;
            }

            if (b >= 65 && b <= 90 || b >= 97 && b <= 122) {
                sbtemporary.append(c);
            } 

            if (b == 32 && sbtemporary.length() != 0){
                for (int j = 1; j<= num; j  ){
                  sb.append(" "   sbtemporary);
                }
                sbtemporary.delete(0,sbtemporary.length());
              }
              sb.append(c);
        }

        String str = sb.toString();
        return str;
    }
 

uj5u.com熱心網友回復：

你可以簡單地這樣做，

String content =  "How are you? I am fine.";
String[] words = content.split("\\s"); // `\\s` preserves any 2 or more repeated spaces

StringBuilder builder = new StringBuilder();
for(String word : words) {
    for(int i = 0; i < n; i  ) { // n is the no. of times to repeat the word
        builder.append(word).append(" ");
    }
}

System.out.printf("Repeated String : %s", builder.toString().trim());

Java8 的一種更整潔的方式，這里 Collections.nCopies(n, word)簡單地回傳一個單詞重復n次數的串列，將其轉換為一個String由空格分隔的單個字串，最終，所有這些重復的字串都轉換為一個由空格分隔的最終結果字串。

String content =  "How are you? I am fine.";
String[] words = content.split("\\s");

String result = Arrays.stream(words)
                .map(word -> String.join(" ", Collections.nCopies(n, word)))
                .collect(Collectors.joining(" ")); //n is the no. of times to repeat the word
System.out.printf("Repeated String : %s", result);

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