我對編碼很陌生，我正在練習一些陣列操作。基本上，我正在嘗試組織這個陣列：
const sequence = ["abc", "abcd", "bca", "bdc", "cbd", "bdc", "acb"];
像這樣：
[[ 'abc', 'bca', 'acb'], ['bdc', 'cbd', 'bdc'], ['abcd']]
到目前為止，這就是我所擁有的：
const sequence = ["abc", "abcd", "bca", "bdc", "cbd", "bdc", "acb"];
let finalSequence = [];
let sequence2 = [];
let sequence3 = [];
let sequence4 = [];
sequence.forEach(element => {
for (const elem of element ) {
sequence2 = sequence.filter(e => e.includes(elem) && e.length === element.length)
sequence3 = sequence.filter(e => !e.includes(elem))
sequence4 = sequence.filter(e => e.includes(elem) && e.length !== element.length)
return sequence2, sequence3, sequence4
}
})
console.log(sequence2)
console.log(sequence3)
console.log(sequence4)
finalSequence.push(sequence2, sequence3, sequence4)
這僅適用于提供的陣列，但是一旦我開始測驗它并更多地使用它，很明顯這不是解決它的正確方法。
非常感謝有關如何解決此問題的任何建議或意見。非常感謝！
uj5u.com熱心網友回復：
您可以標準化每個字串以獲得排序的字母，并將其用作所有相似字串的組。
const
sequence = ["abc", "abcd", "bca", "bdc", "cbd", "bdc", "acb"],
grouped = Object.values(sequence.reduce((r, s) => {
const key = Array.from(s).sort().join('');
(r[key] ??= []).push(s);
return r;
}, {}));
console.log(grouped);轉載請註明出處，本文鏈接：https://www.uj5u.com/gongcheng/333894.html
標籤：javascript 数组 排序
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